Matthias99
Diamond Member
- Oct 7, 2003
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Originally posted by: Skotty
Also, can you mathematically proove that .000...infinity...001 is equal to 0? I know it's easy to prove .9 repeating is equal to 1 by simply multiplying by 10 and cancelling out the .9 repeating. Through that you could claim that .9 repeating + .0...1 is equal to 1, and since .9 repeating is equal to 1, .0...1 must equal 0, but I'm not sure that is mathematically sound.
Mathematically, "0.0000...0001" is not a number (at least not a real or complex number). There's no way to actually define it. Logically, an "infinite number of zeroes followed by a one" cannot exist, since if there is a 1 at the end the zeroes would not actually be infinite.
"0.9999..." is actually "the limit as x goes to infinity of (the sum of i from 1 to x of (9 * (1/(10^i)))" -- that is, 0.9 + 0.09 + 0.009 + 0.0009 + ..., which is a well-defined infinite arithmetic series. This series is exactly equal to one.
The best you can do for "0.000...0001" is "the limit as x goes to infinity of (1/(10^x))". This limit is actually what you get when you take 1 and subtract (0.9 + 0.09 + 0.009 + ...) from it. That limit is exactly equal to 0 -- that's the way limits are defined.