# So a man is climbing up the face of a mountain when...

#### SithSolo1

##### Diamond Member
I'm just not seeing what to do here:

A 50Kg can exert 750J/s of power. How long will it take him to climb a 900m mountain?

#### SithSolo1

##### Diamond Member
I can't be the only one on this board taking physics. You don't have to solve if you don't want to, just point my in the right direction. Heck, any direction would help.

#### eakers

##### Lifer
i thought you were going to make a joke.

ps: f =ma

#### Savarak

##### Platinum Member
depends on how many Powersauce bars he eats

#### Shooters

##### Diamond Member
I may not be understanding the question correctly, but are you saying that you have a 50kg person climbing a vertical distance of 900m and that person produces 750J/s of power?

You know that

work = force x distance
power = work / time

You are given the mass of the person, climb distance, and power. From there you should be able to use the two above equations to solve for time.

#### eakers

##### Lifer
wait, no

i would use f = ma but break acceleration up into distance/time^2 and solve for time

#### Kanalua

##### Diamond Member
You think that's a hard question? My Video Production and Editing Group just wrapped up shooting, and after just capturing the video of our first shoot (about 2 weeks ago), I see that the most important shots of the first scene were taped over by our camera man!!!

#### enginjon

##### Senior member
shooters sounds good to me

g=gravity (9.8m/s^2)
W= 50*g*900
W= 45000g

750 = 45000g/t
t = 45000g/750

t = 60g = 588s

You could also look at it as when he reaches the top he'll have a potential energy
PE=mgh
Then at a rate of 750J/s, how many s to get to (PE=mgh=45000g)J

Its all the same math.

darn double post