Simple physics question

[dighn]

Originally posted by: Vegitto
I don't know the distance (that's what the question is ).. And I also don't know the change in height. Sorry for being so hard on you .

that's why you put everything into an equation then solve for the unknown eg

screwn it:

1/2mv^2 = f*d + m*g*sin(10)*d (height = sin(10)*d)

the only unknown is d

 

[nycxandy]

Originally posted by: Vegitto
I don't know the distance (that's what the question is ).. And I also don't know the change in height. Sorry for being so hard on you .

EDIT: You reckon height and distance are related? Man, this is hard..

Yes, they're related. It's a 10 degree slope upward.

 

[Vegitto]

Originally posted by: dighn

Originally posted by: Vegitto
I don't know the distance (that's what the question is ).. And I also don't know the change in height. Sorry for being so hard on you .

that's why you put everything into an equation then solve for the unknown eg

screwn it:

1/2mv^2 = f*d + m*g*sin(10)*d (height = sin(10)*d)

the only unknown is d

Man, you rock . Thanks! I think I kind of get it..

EDIT: Of course, sin! Damn.. Thanks, man.

 

[Vegitto]

dighn, do you have PayPal? I don't have much, but it's better than nothing .

Edit: PM me!

 

[Goosemaster]

Originally posted by: Vegitto

Originally posted by: dighn

Originally posted by: Vegitto
I don't know the distance (that's what the question is ).. And I also don't know the change in height. Sorry for being so hard on you .

that's why you put everything into an equation then solve for the unknown eg

screwn it:

1/2mv^2 = f*d + m*g*sin(10)*d (height = sin(10)*d)

the only unknown is d

Man, you rock . Thanks! I think I kind of get it..

EDIT: Of course, sin! Damn.. Thanks, man.

yeah, uhuh *pickign soemthign out of his teeth*

sure you do....


*waits for the kid to come back*

 

[jagec]

Originally posted by: Vegitto
Car (1000kg) traveling at 13 8/9th m/s. Car stops just before it reaches a mountain(ish thingie) going up 10 degrees. (So, you're on the flat side, and you're about to go up.)
Whilst ascending, the car undergoes an average 100N in Ffriction. How far can the car go until it loses its speed?
Also calculate Fmotor.

I'm confused...you're travelling at ~14 m/s, you stop right before a slope...what's the question? The only way to ascend is to start the car moving again, in which case it can go as far as it likes until it runs out of gas, and assuming a constant speed, Fmotor=Ffriction+Fdrag+delta(potential energy).

 

[Vegitto]

Originally posted by: Goosemaster

Originally posted by: Vegitto

Originally posted by: dighn

Originally posted by: Vegitto
I don't know the distance (that's what the question is ).. And I also don't know the change in height. Sorry for being so hard on you .

that's why you put everything into an equation then solve for the unknown eg

screwn it:

1/2mv^2 = f*d + m*g*sin(10)*d (height = sin(10)*d)

the only unknown is d

Man, you rock . Thanks! I think I kind of get it..

EDIT: Of course, sin! Damn.. Thanks, man.

yeah, uhuh *pickign soemthign out of his teeth*

sure you do....


*waits for the kid to come back*

Heh. No, I got this..

Originally posted by: jagec

Originally posted by: Vegitto
Car (1000kg) traveling at 13 8/9th m/s. Car stops just before it reaches a mountain(ish thingie) going up 10 degrees. (So, you're on the flat side, and you're about to go up.)
Whilst ascending, the car undergoes an average 100N in Ffriction. How far can the car go until it loses its speed?
Also calculate Fmotor.

I'm confused...you're travelling at ~14 m/s, you stop right before a slope...what's the question? The only way to ascend is to start the car moving again, in which case it can go as far as it likes until it runs out of gas, and assuming a constant speed, Fmotor=Ffriction+Fdrag+delta(potential energy).

No, it didn't stop.. The motor died. Sorry for explaining it wrong.