Simple math question

[Dari]

I have a problem in an economics class similar to this. But I need to find the inverse function of y=(1-2^x)/(1+2^x). It's been a while since I've taken calculus. Can anyone here help me? Thanx in advance.

 

[minendo]

(1+2^x)/(1-2^x)

 

[Dari]

Originally posted by: minendo
(1+2^x)/(1-2^x)

I thought about that but I don't think it's that easy. Am I wrong?

EDIT: You're correct but can it be simplified further to isolate y?

 

[minendo]

Originally posted by: Dari

Originally posted by: minendo
(1+2^x)/(1-2^x)

I thought about that but I don't think it's that easy. Am I wrong?

Of course it is not that easy.

 

[HonkeyDonk]

replace the any X with Y and any Y with X and solve for Y.

Of course it might be hard, but give it a shot.

 

[Soccerman06]

Originally posted by: HonkeyDonk
replace the any X with Y and any Y with X and solve for Y.

Of course it might be hard, but give it a shot.

right

This isnt Calc, its simple algebra, so put y in for x and your set, thats the inverse of a function.

 

[Dari]

Originally posted by: Soccerman06

Originally posted by: HonkeyDonk
replace the any X with Y and any Y with X and solve for Y.

Of course it might be hard, but give it a shot.

right

This isnt Calc, its simple algebra, so put y in for x and your set, thats the inverse of a function.

That's the problem I'm having. I forgot how to isolate y if it's an exponent. Should I treat it as an algorithm?

 

[Splork]

if it's in the exponent, wouldn't you treat it as a logrithm? It's been awhile, so don't quote me.

-sp

 

[illusion88]

Originally posted by: Splork
if it's in the exponent, wouldn't you treat it as a logrithm? It's been awhile, so don't quote me.

-sp

I quoted you!

And yes you would.

 

[Splork]

Originally posted by: illusion88

Originally posted by: Splork
if it's in the exponent, wouldn't you treat it as a logrithm? It's been awhile, so don't quote me.

-sp

I quoted you!

And yes you would.

Oh Snap! It's been awhile since I've been quoted. Thx.

-sp

 

[Splork]

x + xylog2 + ylog2 = 1

-sp

Someone correct me if I'm wrong.

 

[desteffy]

hmm...