Simple math problem....

[jinduy]

is there a shortcut to solving the modulus for (1+i)^10 ?

ack

 

[The Stigenator]

easy..

run this thru a calculator 1^10 + (-1)^5

edit: answer = 0 i think.

 

[Mrfrog840]

i being an imaginary #?

 

[jinduy]

yes i is imaginary, i = sqtrt(-1)

 

[dopcombo]

Mod(1+i)^2 = (1+i)(1-i) = 1+1 =2
2^5 =32 (because ^10 at first. so now. there are 5 sets of this.)

Correct? hehe

Try working out the ^2 one and see whether u get 2. hehe.
Its been so long since i did this sort of thing.

 

[jinduy]

yes you are correct about mod(1+i)^2 = 2, hmm ur theory sounds correct, thanks, i will try to veryify

 

[jinduy]

how bout another problem to tickle your minds? last problem, i havent tried yet but i'll do it right now, same question, but now find modulus of

(4-2i)^2 - (2-i)^3