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simple circuit question

Omegachi

Diamond Member
how do you calculate the voltage after going through a resistor in a simple circuit where there is only the voltage source and a resistor?


-----WW-----
| |
( Vs ) |
| |
|_________|
 
What you have described is not a complete circiut, there will be no voltage drop until you have a current. So the answer to your question is... It depents on the current draw.

Ohms law (V=IR)gives you the voltage drop across a resistance R for a current I.
 
The voltage is Vs, since very little current will be flowing (given a volt meter with a very high input impedance). The resistor's resistance must be << Ri of the volt meter.
 
Originally posted by: Omegachi
how do you calculate the voltage after going through a resistor in a simple circuit where there is only the voltage source and a resistor?


-----WW-----
| |
( Vs ) |
| |
|_________|

you don't. the voltage will always be equal to Vs (which is why its a voltage source). the only thing you can calculage is the current, which is Vs/R.


 
well, the original problem is like this:

pic

i need to calculate the Vss and the Iss. no current is given but i know the Vs and the 2 resistor value. i was thinking that the R2 gets shorted so we could treat this circuit as what i have describe in my first post....
 
Originally posted by: Omegachi
well, the original problem is like this:

pic

i need to calculate the Vss and the Iss. no current is given but i know the Vs and the 2 resistor value. i was thinking that the R2 gets shorted so we could treat this circuit as what i have describe in my first post....

that shows R2 shorted to ground. Can you draw a volt meter around where you want to measure the voltage you are asking - I'm getting confused.
 
hmm... i guess i want to find the voltage at the intersection of the r1 r2 and the short wire.

i just want the Vss and Iss.
 
R2 is shorted, so disregard it.

the voltage across R1 is the full supply voltage.


edit: cant tell you current until you tell us the value of R1 and the value of the voltage source. once you know that its just V/R = I
 
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