Sigma math question problem

[imported_K3N]

the answer for the following problem is supposed to be 107, but i dont know how to get it

http://img165.imagevenue.com/loc549/th_88443_dfdf_122_549lo.JPG

i did ((3+10)*8) divided by 2 , and i got 52, may someone tell me how to get 107?

 

[Umberger]

i get 52.

edit: 3+4+5+6+7+8+9+10 = 52

 

[StevenYoo]

i also got 52

 

[RedArmy]

Yeah I got 52 as well. The sum from 3 to 10...I'm not sure how 107 is a possible answer either

 

[Brainonska511]

Originally posted by: Umberger
i get 52.

edit: 3+4+5+6+7+8+9+10 = 52

:thumbsup:

 

[Umberger]

Originally posted by: Brainonska511

Originally posted by: Umberger
i get 52.

edit: 3+4+5+6+7+8+9+10 = 52

:thumbsup:

...thanks for the confirmation... i would be upset if i couldn't do that... Math minor FTW! :beer:

 

[SpecialEd]

the answer is 52.

trust your brain, not some answer book.

 

[imported_K3N]

I've been doing a match placement test review, and the answer it said was 107, so hopefully they are wrong and we are right...

 

[villageidiot111]

52

 

[FleshLight]

If it's (2N + 3/8) you will get 104 =)

 

[eLiu]

Here's my theory for how they got 107 (it's wrong: the answer is 52).

a correct method: the sum of n from n = 1 to 10 is 10*11/2 = 55. But we skipped n = 1 and 2, so it's 55 - 1 - 2 = 52.

But if you forget to divide by 2... then:
(this is wrong!) sum of n from n = 1 to 10 is 10*11 = 110. But we skipped n = 1 and 2, so 110 - 1 - 2 = 107.

I'm guessing they fvcked up the summation formula.

 

[habib89]

it's definately 52

 

[potoba]

13*4=52 !!!
lol, you need more than 10 times of 10 to get 107 and you dont even have 10 terms...