Serious Math Help Needed

WhoIsThat

Senior member
Dec 27, 2002
362
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Argh, I have no idea how to do this problem. I think I understand conceptually what an affine transformation is, and what this question is asking, but my brain is completely blank on how to do this question, and have been staring at it for hours.

Click for the question.

Help!
 

BigJ

Lifer
Nov 18, 2001
21,330
1
81
Is that russian? Cause I don't understand what the hell that question is asking. What level Math is this?
 

GtPrOjEcTX

Lifer
Jul 3, 2001
10,784
6
81
Briefly understand it. The 3space is Calc 3 and above level for those interested.

Not quite sure how to approach it though.

I think I understand conceptually what an affine transformation is
Then you've got some on me then. GL
 

WhoIsThat

Senior member
Dec 27, 2002
362
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0
Well, it's not my handwriting. This is a theoritical calculus class that's about three classes after Cal III.

We are only learning background information for the main subject, and this is a question on some of the background stuff we must know. :(
 

WhoIsThat

Senior member
Dec 27, 2002
362
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0
I think the part that really throws me off is the inequality part. How do I deal with the inequality part?
 

Fatalist

Member
Nov 25, 2001
26
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0
I'm thinking that the inequality just means that P0, P1, and P2 are not colinear, but I could be wrong.
 

TuxDave

Lifer
Oct 8, 2002
10,571
3
71
Soo.... this is what I get (minus all the mumbo jumbo in the paragraph)

You need a transformation matrix that will:

Decompose your vector of (xo,yo)-(x,y) into components of (xo,yo)-(x1,y1) and (xo,yo)-(x2,y2) and set the magnitudes of those components as your new x and y coordinate?
 

TuxDave

Lifer
Oct 8, 2002
10,571
3
71
Originally posted by: Fatalist
I'm thinking that the inequality just means that P0, P1, and P2 are not colinear, but I could be wrong.

Yes... that's exactly what I think it means. Otherwise you cannot make a clear cut transformation.
 

bigalt

Golden Member
Oct 12, 2000
1,525
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I'm stumped.

it should be

[x'] = [a1 a2] [x] + [b1 b2]
[y'] = [a3 a4] [y] + [b3 b4]

but you have 8 unknowns, and 3 points gives you 6 equations. no idea how to solve it.
 

Fatalist

Member
Nov 25, 2001
26
0
0
Change of basis just uses P1 and P2 as the rows or columns of M, IIRC.
Use a linear algebra textbook.