RIDDLES! Or, are you smarter than the rest of us?

[Flyermax2k3]

Here's a new one:
The man who invented it doesn't want it, the man who bought it doesn't need it, and the man who needs it doesn't know it. What is it?

 

[Descartes]

Originally posted by: Flyermax2k3
Here's a new one:
The man who invented it doesn't want it, the man who bought it doesn't need it, and the man who needs it doesn't know it. What is it?

Coffin.

 

[Flyermax2k3]

Originally posted by: Descartes

Originally posted by: Flyermax2k3
Here's a new one:
The man who invented it doesn't want it, the man who bought it doesn't need it, and the man who needs it doesn't know it. What is it?

Coffin.

ding ding ding!

That was too easy....

 

[Orsorum]

Originally posted by: Flyermax2k3
Here's a new one:
The man who invented it doesn't want it, the man who bought it doesn't need it, and the man who needs it doesn't know it. What is it?

A young girl?

 

[Flyermax2k3]

New one:
What is it that belongs to you, but others use it more than you do?

 

[Descartes]

Originally posted by: Flyermax2k3
New one:
What is it that belongs to you, but others use it more than you do?

Come on man, your name.

Neeeeeeeext! Let's find some that are less well-known

 

[CaseTragedy]

Originally posted by: Flyermax2k3
New one:
What is it that belongs to you, but others use it more than you do?

My digital camera? Fvcking leechers.


(or) my Name.


-Case

 

[Descartes]

damnit, nm.

 

[Flyermax2k3]

Originally posted by: Descartes

Originally posted by: Flyermax2k3
New one:
What is it that belongs to you, but others use it more than you do?

Come on man, your name.

Neeeeeeeext! Let's find some that are less well-known

The only ones I know are well-known
Why don't YOU come up with some?

 

[Descartes]

Try this one:

There are three switches in a hallway. One switch controls a light fixture in a room at the far end of the hall. The door to the room is closed, and you can't see whether the light is on or off. You need to find out which of the three switches controls the light. How can you be certain of finding that out, making just one trip to the room?

[edit]I'll tell everyone what answer I gave if no one gets it.[/edit]

 

[Flyermax2k3]

Originally posted by: Descartes
Try this one:

There are three switches in a hallway. One switch controls a light fixture in a room at the far end of the hall. The door to the room is closed, and you can't see whether the light is on or off. You need to find out which of the three switches controls the light. How can you be certain of finding that out, making just one trip to the room?

[edit]I'll tell everyone what answer I gave if no one gets it.[/edit]

The only thing I can think of is that 2 of the switches control lights which are visible outside of the room so one could just play with the switches until he finds one that doesn't do anything
Otherwise I have no idea

 

[Orsorum]

Originally posted by: Descartes
Try this one:

There are three switches in a hallway. One switch controls a light fixture in a room at the far end of the hall. The door to the room is closed, and you can't see whether the light is on or off. You need to find out which of the three switches controls the light. How can you be certain of finding that out, making just one trip to the room?

[edit]I'll tell everyone what answer I gave if no one gets it.[/edit]

Flip the switches: one should operate the hallway light. Flip another one, and walk down to the room to check, if the light isn't on, it's the last switch.

 

[Descartes]

Originally posted by: Flyermax2k3

Originally posted by: Descartes
Try this one:

There are three switches in a hallway. One switch controls a light fixture in a room at the far end of the hall. The door to the room is closed, and you can't see whether the light is on or off. You need to find out which of the three switches controls the light. How can you be certain of finding that out, making just one trip to the room?

[edit]I'll tell everyone what answer I gave if no one gets it.[/edit]

The only thing I can think of is that 2 of the switches control lights which are visible outside of the room so one could just play with the switches until he finds one that doesn't do anything
Otherwise I have no idea

Nope, that would mean the question were a trick. You are only allowed to identify the state of the bulb once, and you have no outside indicators.

 

[PowerEngineer]

Originally posted by: Descartes
Try this one:

There are three switches in a hallway. One switch controls a light fixture in a room at the far end of the hall. The door to the room is closed, and you can't see whether the light is on or off. You need to find out which of the three switches controls the light. How can you be certain of finding that out, making just one trip to the room?

[edit]I'll tell everyone what answer I gave if no one gets it.[/edit]

Turn one one switch; leave it on for about five minutes, then turn it off.

Turn on a second switch, and go down the hall.

If the light is on, then (obviously) it's switch two. If the light is off but the bulb is warm , then it's switch one. If the light is off and the bulb is cold, then it's switch three.

 

[Descartes]

Originally posted by: Orsorum

Originally posted by: Descartes
Try this one:

There are three switches in a hallway. One switch controls a light fixture in a room at the far end of the hall. The door to the room is closed, and you can't see whether the light is on or off. You need to find out which of the three switches controls the light. How can you be certain of finding that out, making just one trip to the room?

[edit]I'll tell everyone what answer I gave if no one gets it.[/edit]

Flip the switches: one should operate the hallway light. Flip another one, and walk down to the room to check, if the light isn't on, it's the last switch.

Nope. There are no tricks to the question, and there are no other indicators. One switch operates the light in the closed room (and no light escapes), and the other two are dummy switches.

 

[Descartes]

Originally posted by: PowerEngineer

Originally posted by: Descartes
Try this one:

There are three switches in a hallway. One switch controls a light fixture in a room at the far end of the hall. The door to the room is closed, and you can't see whether the light is on or off. You need to find out which of the three switches controls the light. How can you be certain of finding that out, making just one trip to the room?

[edit]I'll tell everyone what answer I gave if no one gets it.[/edit]

Turn one one switch; leave it on for about five minutes, then turn it off.

Turn on a second switch, and go down the hall.

If the light is on, then (obviously) it's switch two. If the light is off but the bulb is warm , then it's switch one. If the light is off and the bulb is cold, then it's switch three.

Nice. :beer:

 

[Descartes]

Ok, another one...

You have two lengths of fuse. Each will burn for exactly one hour. But the fuses are not necessarily identical and do not burn at a constant rate. There are fast-burning sections and slow-burning sections. How do you measure forty-five minutes using only fuses and a lighter?

 

[Flyermax2k3]

Originally posted by: Descartes
Ok, another one...

You have two lengths of fuse. Each will burn for exactly one hour. But the fuses are not necessarily identical and do not burn at a constant rate. There are fast-burning sections and slow-burning sections. How do you measure forty-five minutes using only fuses and a lighter?

If you're McGuyver you'll turn the fuses and the lighter into a stopwatch and time those 45 minutes

 

[Descartes]

Originally posted by: Flyermax2k3

Originally posted by: Descartes
Ok, another one...

You have two lengths of fuse. Each will burn for exactly one hour. But the fuses are not necessarily identical and do not burn at a constant rate. There are fast-burning sections and slow-burning sections. How do you measure forty-five minutes using only fuses and a lighter?

If you're McGuyver you'll turn the fuses and the lighter into a stopwatch and time those 45 minutes

Points for out-of-the-box thinking :beer:

 

[PowerEngineer]

Originally posted by: Descartes
Ok, another one...

You have two lengths of fuse. Each will burn for exactly one hour. But the fuses are not necessarily identical and do not burn at a constant rate. There are fast-burning sections and slow-burning sections. How do you measure forty-five minutes using only fuses and a lighter?

Light one fuse at one end and the other fuse at both ends. When the second fuse burns out completely (at 30 minutes), light the second end of the first fuse (which will then burn out in another 15 minutes).

 

[marquee]

Try this one:

There are three switches in a hallway. One switch controls a light fixture in a room at the far end of the hall. The door to the room is closed, and you can't see whether the light is on or off. You need to find out which of the three switches controls the light. How can you be certain of finding that out, making just one trip to the room?

[edit]I'll tell everyone what answer I gave if no one gets it.[/edit]

walk over and open the damn door, then return to the switches and see which one lights the room

 

[silverpig]

You have 12 golf balls, 11 of which are the same weight, one of which has a deviant weight, and are allowed to use a balance scale 3 times. BUT, you do not know whether the deviating golf ball is heavier or lighter than the rest. Using the scale 3 times, you have to point out the deviating ball AND tell whether it?s heavier or lighter than the rest.

 

[fyleow]

I'm going to say black.

 

[TuxDave]

Originally posted by: silverpig
You have 12 golf balls, 11 of which are the same weight, one of which has a deviant weight, and are allowed to use a balance scale 3 times. BUT, you do not know whether the deviating golf ball is heavier or lighter than the rest. Using the scale 3 times, you have to point out the deviating ball AND tell whether it?s heavier or lighter than the rest.

I hate this riddle cuz the answer is so damn long to explain.

 

[Descartes]

Originally posted by: PowerEngineer

Originally posted by: Descartes
Ok, another one...

You have two lengths of fuse. Each will burn for exactly one hour. But the fuses are not necessarily identical and do not burn at a constant rate. There are fast-burning sections and slow-burning sections. How do you measure forty-five minutes using only fuses and a lighter?

Light one fuse at one end and the other fuse at both ends. When the second fuse burns out completely (at 30 minutes), light the second end of the first fuse (which will then burn out in another 15 minutes).

You win...again!