Originally posted by: mobobuff
Originally posted by: Goosemaster
If I square the number, is it less than, equal to, or greater than four.
Winnar.
How is that a yes or no question?
Originally posted by: mobobuff
Originally posted by: Goosemaster
If I square the number, is it less than, equal to, or greater than four.
Winnar.
Originally posted by: apac
Maybe something to do with the Pythagorean theorem? A right triangle with sides of length 1, 2 and 3.
Originally posted by: b0mbrman
Originally posted by: mobobuff
Originally posted by: Goosemaster
If I square the number, is it less than, equal to, or greater than four.
Winnar.
How is that a yes or no question?
Originally posted by: Goosemaster
Originally posted by: apac
Maybe something to do with the Pythagorean theorem? A right triangle with sides of length 1, 2 and 3.
345....this is not 345
Originally posted by: RedArmy
Read the OP again, my friend just informed me it was one "yes or no" question...F'ing a.
Originally posted by: Goosemaster
Originally posted by: b0mbrman
Originally posted by: mobobuff
Originally posted by: Goosemaster
If I square the number, is it less than, equal to, or greater than four.
Winnar.
How is that a yes or no question?
he just added the yes or no part...
Originally posted by: dighn
this is a bit contrived but... "I'm thinking of a number betwen 1.5 or 2, is your number > than mine?"
yes - 3
no - 1
maybe - 2
Originally posted by: Leros
How can a yes or not question answer this? yes/no describes two options but there are three numbers to choose from.
Originally posted by: DrPizza
if he answers no, the answer is 2
Originally posted by: Chaotic42
Originally posted by: DrPizza
if he answers no, the answer is 2
Don't worry Bender, there's no such thing as 2.
Originally posted by: Goosemaster
Originally posted by: Chaotic42
Originally posted by: DrPizza
if he answers no, the answer is 2
Don't worry Bender, there's no such thing as 2.
:laugh:
Best nightmare-in-a-hit-comedy-series-EVER
Originally posted by: mobobuff
Originally posted by: Goosemaster
Originally posted by: Chaotic42
Originally posted by: DrPizza
if he answers no, the answer is 2
Don't worry Bender, there's no such thing as 2.
:laugh:
Best nightmare-in-a-hit-comedy-series-EVER
If you freeze-frame, there WAS a 2 in the nightmare.
Originally posted by: DrPizza
I think that coming up with a math equation for which the answer is very simple to find for two of the values, and difficult to find for the 3rd value might be the way to go.
i.e. if he answers yes, the answer is 1.
if he answers no, the answer is 2
if he cannot answer the question because the problem is unsolvable in a realistic amount of time, then the answer is 3
see: http://en.wikipedia.org/wiki/Complexity_classes_P_and_NP
Originally posted by: silverpig
Originally posted by: DrPizza
I think that coming up with a math equation for which the answer is very simple to find for two of the values, and difficult to find for the 3rd value might be the way to go.
i.e. if he answers yes, the answer is 1.
if he answers no, the answer is 2
if he cannot answer the question because the problem is unsolvable in a realistic amount of time, then the answer is 3
see: http://en.wikipedia.org/wiki/Complexity_classes_P_and_NP
Give him some instructions like:
Assign the value of your number to the variable x. Compute (x-1)^(51200329123/443). Does the number which results from this computation have a 0 in the "ones" (first to the left of the decimal) place?
If x = 1, then the number is 0, and he'll answer yes.
If x = 2, then the number is 1, and he'll answer no.
If x = 3, then he'll have to do a lot of crunching and you'll know it's 3.
Originally posted by: silverpig
Originally posted by: DrPizza
I think that coming up with a math equation for which the answer is very simple to find for two of the values, and difficult to find for the 3rd value might be the way to go.
i.e. if he answers yes, the answer is 1.
if he answers no, the answer is 2
if he cannot answer the question because the problem is unsolvable in a realistic amount of time, then the answer is 3
see: http://en.wikipedia.org/wiki/Complexity_classes_P_and_NP
Give him some instructions like:
Assign the value of your number to the variable x. Compute (x-1)^(51200329123/443). Does the number which results from this computation have a 0 in the "ones" (first to the left of the decimal) place?
If x = 1, then the number is 0, and he'll answer yes.
If x = 2, then the number is 1, and he'll answer no.
If x = 3, then he'll have to do a lot of crunching and you'll know it's 3.
Originally posted by: Goosemaster
Originally posted by: silverpig
Originally posted by: DrPizza
I think that coming up with a math equation for which the answer is very simple to find for two of the values, and difficult to find for the 3rd value might be the way to go.
i.e. if he answers yes, the answer is 1.
if he answers no, the answer is 2
if he cannot answer the question because the problem is unsolvable in a realistic amount of time, then the answer is 3
see: http://en.wikipedia.org/wiki/Complexity_classes_P_and_NP
Give him some instructions like:
Assign the value of your number to the variable x. Compute (x-1)^(51200329123/443). Does the number which results from this computation have a 0 in the "ones" (first to the left of the decimal) place?
If x = 1, then the number is 0, and he'll answer yes.
If x = 2, then the number is 1, and he'll answer no.
If x = 3, then he'll have to do a lot of crunching and you'll know it's 3.
That assumes that time is also a factor.