restored image to SSD, now painfully slow and out of alignment

Maximus96

Diamond Member
Nov 9, 2000
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I used acronis 2010 to make an image of my intel 120gb ssd last week. After restoring that image to the same ssd, it became painfully slow to do any task. i googled a bit and found that the small ~150mb partition may be out of alignment. however, everything i read said to format/re-install win7 to fix the alignment issue.

is it possible to fix the offset alignment without format/re-install?

thanks
 

Maximus96

Diamond Member
Nov 9, 2000
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i googled and found the gpart live cd which looks like it would work. i'll try it tonight.

however, i still don't understand how the alignment can get screwed up when the image that came from the same ssd drive was only a few days old...i'm starting to worry that acronis image/restore is not a safe method for backing up drives...
 

Elixer

Lifer
May 7, 2002
10,371
762
126
The imaging software must fully support SSDs.
All you really had to do is create a 1MB partition at the begining, then use the rest of the free space for the clone.
Done.
 

Maximus96

Diamond Member
Nov 9, 2000
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i'm guessing acronis 2010 doesn't fully support SSDs then?

so in addition to the ~150mb partition, i need to make another 1mb partition, for a total of 3?
 

zephyrprime

Diamond Member
Feb 18, 2001
7,512
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i'm guessing acronis 2010 doesn't fully support SSDs then?

so in addition to the ~150mb partition, i need to make another 1mb partition, for a total of 3?

It was common in the past to start a partition on the 63rd sector. However, because this is not evenly divisible by 4K (the common SSD block size), it causes each OS cluster (typically 4K) to cross SSD block boundaries and degrade performance (should not be a huge degradation though). Newer os partition starting at 1MB so they don't have this problem anymore. It's possible that acronis restored your paritition at the 63rd sector which is what was customarily done in the past rather than at the original location of your partition. Just speculating.