Really cool little abstract thinking exercise

[JasGamer]

If x=.999... (meaning .999... repeating into infinity)


then 10x = 9.999... (again, 9.999... repeating into infinity)


Then it stands to reason that 9x will be found from the equation: (10x)-(x)=(9x) This of course holds true.


Therefore, if 10x=(9.999...) and x=(.999...) then (9.999...) - (.999...) = 9x


Thus we find that 9x is exactly equal to the integer 9


Basic algebra: 9x=9, (9x=9)/(9) = (1x=1) where X represents .999...


Therefore .999... repeating into infinity is exactly equal to 1.

 

[Ikonomi]

It's baaaaaaaaack. :Q

 

[Colt45]

R

 

[t3hmuffinman]

there's also a proof to show that 0 = 1... someone showed it to me once, can't remember it though