quick, whats the antiderivative of (sinx)^2

[cirthix]

please
dumb me, i forgot to look at double angle formulas, problem solved, thanks guys
all done

 

[Sheepathon]

 

[cirthix]

i'm doing homework, skipped that problem, but i'll be done with everything but that problem in like 10 minutes, an dwould like to have it all done

 

[Sheepathon]

 

[DotheDamnTHing]

four

 

[StrangerGuy]

42?

 

[Darien]

x/2 - 1/4 * Sin(2x)

EDIT: http://integrals.wolfram.com/

 

[cirthix]

cool link, but i can't get it to work properly, it keeps thinking s, i, and n are variables lol

edit: brackets not parentheses, bleh. awesome link though, so fun!

 

[cmp1223]

tricky... maybe think of it as (sinx)(sinx) and use integration by parts

u=sinx dv=sinx
du=cosx v=-cosx

= (sinx)(-cosx)- integral[-cosx(cos)}

yikes.. it starts over sorry

 

[Darien]

You have to use a double angle formula for the integration:

Cos[2x] = 1 - 2*Sin[x]*Sin[x]