quick physics question

[GoingUp]

I dont remember it correctly and I cant find it the way I want it on google.

Something like -9.8m/s2 + something + height started at.

 

[Indolent]

gravity equation? you might mean for a falling object. It think it's

y = 1/2* 9.8m/s^2 * t^2 + vo * t + ho

vo=initial velocity
ho=initial height
y=distance it fell over that amount of time


*added spacing for clarity

 

[OOBradm]

height = iVel * Time + 0.5 * accel * time ^2


S = Vo*T + .5*A*T^2

 

[Gibsons]

Originally posted by: Gobadgrs
I dont remember it correctly and I cant find it the way I want it on google.

Something like -9.8m/s2 + something + height started at.

the value of G on earth near sea level ?

9.8 meters per second squared
or
9.8m/sec^2

edit: oops, saw you wanted height in it too. nm!

 

[SilentVixen]

V=IR LOL

 

[Indolent]

Originally posted by: OOBradm
height = iVel * Time + 0.5 * accel * time ^2


S = Vo*T + .5*A*T^2

yeah, I missed a 1/2 in mine

 

[LordMorpheus]

F = GMm/(r^2)

oo, you wanted the wussy approximation.

Yeah, then its above, but . .

S = Ho + Vo*t - 1/2 * 9.8 * t^2

 

[MrDudeMan]

dang, got in here too late.

its actually x(final) - x(initial) = velocity(initial)*t + 1/2*g*t^2

you guys are all assuming the initial value is from sea level. what if it started a lot higher? hmmm?

edit: replace x with y if you want height, but its the same equation either way. also this is a very poor approximation because of drag. this same equation also works for angular velocity.

 

[Rock Hydra]

E=MC^2