quick math question!

[tommigsr]

If logx = 2log(y), then x = ?

thanx

 

[habib89]

if memory serves me right

10^logx = 2(10^logy)

x = 2y

i'm getting this from my trig book.. it says
a^[log a (x)] = x
that reads: a to the power of [log base a of x] equals x

in this case, a = 10 that's why i used 10

i hope this helps.. i don't know if it's right or not

 

[GoldenBear]

Hmm, you have two variables and you want to solve for one of them? I don't think that's possible?

Goldenbear,

 

[Milhouse99]

He doesn't want a numerical answer but rather what x equals in terms of y.

 

[MereMortal]

log(x) = 2log(y) = log(y^2)

10^(log(x)) = 10^(log(y^2))

x = y^2

 

[rominl]

MereMortal is correct.

 

[Mday]

hehee =P

 

[tommigsr]

thanks kids