Quick math question

LiLRiceBoi

Golden Member
Dec 2, 2000
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I havnet done this stuff in years... but my friend just asked me how to integrate 1/(1+x^4) dx

doenst look very hard but i cant remember this stuff. i'm thinking inverse trig?
 

chuckywang

Lifer
Jan 12, 2004
20,133
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Originally posted by: LiLRiceBoi
I havnet done this stuff in years... but my friend just asked me how to integrate 1/(1+x^4) dx

doenst look very hard but i cant remember this stuff. i'm thinking inverse trig?

I guess integration by parts is your answer.
 

Jonitus

Member
Feb 14, 2002
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Originally posted by: chuckywang
Originally posted by: LiLRiceBoi
Originally posted by: Jonitus
1/x^5 * (1+x^4 - ln|1+x^4|)+C

how did you get that?

TI-89?


Nope. I use calculus everyday, and as such, have had to practically memorize the basic methods of integrating forms of a+bx.

The integral of xdx/(a+bx) is 1/b^2(a+bx-a ln|a+bx|)+C
 

chuckywang

Lifer
Jan 12, 2004
20,133
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Originally posted by: Jonitus
Originally posted by: chuckywang
Originally posted by: LiLRiceBoi
Originally posted by: Jonitus
1/x^5 * (1+x^4 - ln|1+x^4|)+C

how did you get that?

TI-89?


Nope. I use calculus everyday, and as such, have had to practically memorize the basic methods of integrating forms of a+bx.

The integral of xdx/(a+bx) is 1/b^2(a+bx-a ln|a+bx|)+C

But this is the integral of 1/(1+x^4).

btw, what do you do?
 

Jonitus

Member
Feb 14, 2002
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I know what you're trying to integrate. The example I gave is a basic form like you would see if you consulted a table in a decent text book. That computer-generated answer is crap...about as handy as if you had Mathematica doing it...the program over-complicates it. Look, compare the xdx/a+bx with the equation you need solved...1/(1+x^4)...x=1, a=1, b=1,...what's so confusing here?

See here...first example...just like I said...

Integration tables