- Jun 28, 2002
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It's been a while since I've had to do inverses, so this may seem dumb
But what is the inverse of 1/(x-3)
But what is the inverse of 1/(x-3)
Originally posted by: Paul180
Inverse as ^-1 is just x-3
but the inverse is y=1/x+3
Originally posted by: Paul180
Inverse as ^-1 is just x-3
but the inverse is y=1/x+3
Originally posted by: Stojakapimp
Originally posted by: Paul180
Inverse as ^-1 is just x-3
but the inverse is y=1/x+3
I'm not exactly sure which inverse it's supposed to be, but I do know that in the domain, x cannot equal 0. So why would that be?
Originally posted by: Stojakapimp
Originally posted by: Paul180
Inverse as ^-1 is just x-3
but the inverse is y=1/x+3
I'm not exactly sure which inverse it's supposed to be, but I do know that in the domain, x cannot equal 0. So why would that be?