Quick inverse question

[Stojakapimp]

It's been a while since I've had to do inverses, so this may seem dumb

But what is the inverse of 1/(x-3)

 

[TheChort]

edit: i feel dumb
edit again: actually, i was right the first time, it is (x-3)/1

 

[Paul180]

Inverse as ^-1 is just x-3

but the inverse is y=1/x+3

 

[TheChort]

Originally posted by: Paul180
Inverse as ^-1 is just x-3

but the inverse is y=1/x+3

how did you get x + 3 ?

 

[Stojakapimp]

Originally posted by: Paul180
Inverse as ^-1 is just x-3

but the inverse is y=1/x+3

I'm not exactly sure which inverse it's supposed to be, but I do know that in the domain, x cannot equal 0. So why would that be?

 

[MeanMeosh]

inverse is just x-3 ... with x != 3

1/(x-3) = (x-3)^-1
inverse of that = ((x-3)^-1)^-1 = (x-3) ^ (-1 * -1) = x-3

however, the domain is all x, such that x != 3, since if x were 3, 1/(x-3) would be undefined)

if its just a simple prob, ignore the domain

 

[TheChort]

Originally posted by: Stojakapimp

Originally posted by: Paul180
Inverse as ^-1 is just x-3

but the inverse is y=1/x+3

I'm not exactly sure which inverse it's supposed to be, but I do know that in the domain, x cannot equal 0. So why would that be?

this would only happen if x is alone in the denomonator, which cant really happen here.

here's a link, CTRL F for "inverse"

 

[LivinLaVivaPollo]

Replace all the x's with y's, and then solve for y.

 

[dighn]

Originally posted by: Stojakapimp

Originally posted by: Paul180
Inverse as ^-1 is just x-3

but the inverse is y=1/x+3

I'm not exactly sure which inverse it's supposed to be, but I do know that in the domain, x cannot equal 0. So why would that be?

x cannot equal to 0 means y cannot equal to 0 in the original equation

y = 1/(3-x)

if y is 0 you can't solve for x