quick basic geometry question

[AznAnarchy99]

I have a square with an area of 25 sq units. how do i find the length of the diagonal

 

[dighn]

find the length of the side, then use pythag to find the diagnal

 

[SVT Cobra]

a square qith?

well you know the sides are each 5unites....and I believe there is some formula that says its like 5 square root two or something

look in your book!

 

[Cooler]

Originally posted by: dighn
find the length of the side, then use pythag to find the diagnal

QFT

 

[SVT Cobra]

Originally posted by: dighn
find the length of the side, then use pythag to find the diagnal

w00t I win...5root two

damn I somehow recalled that out of the blue while typing after all these years

 

[AznAnarchy99]

Originally posted by: Cooler

Originally posted by: dighn
find the length of the side, then use pythag to find the diagnal

QFT

thanks forgot all about pythag.

Originally posted by: Son of a N00b
a square qith?

well you know the sides are each 5unites....and I believe there is some formula that says its like 5 square root two or something

look in your book!

to tell how lazy i am, i dont feel like gettin up, walking to my room, picking up my book, bringing it back here, and opening the open

 

[Xylitol]

Pythag
both sides are 5x5
do 5^2 + 5^2 = C^2
c = squarerootof50
squarerootof50 = diagonal length

 

[alkemyst]

Originally posted by: dighn
find the length of the side, then use pythag to find the diagnal

where a and b are the sides, c is your diagonal (this is simplified in a square, but never forget below and it's just as easy)

a^2+b^2=c^2