• We’re currently investigating an issue related to the forum theme and styling that is impacting page layout and visual formatting. The problem has been identified, and we are actively working on a resolution. There is no impact to user data or functionality, this is strictly a front-end display issue. We’ll post an update once the fix has been deployed. Thanks for your patience while we get this sorted.

Quick Algebra help

Nocturnal

Lifer
Rewrite each multiplication problem as a division problem. There is more than one correct answer.

(x + 3)(x + 1) = 2x^2 + 5x + 3

How the hell do you rewrite it as a division problem?

I need to divide polynomials.
 
So in my answer book it says to put the answer over the (x + 3) can anyone tell me why they do this? Or why that is the proper way?
 
Well if you factor 2x^2 + 5x + 3, you get (2x + 3)(x + 1), and then you can cancel out (x + 1) from both sides. You're left with (x+3)/(2x+3) = 1 if you then divide both sides by (2x + 3)
 
Originally posted by: TMTCC
Well if you factor 2x^2 + 5x + 3, you get (2x + 3)(x + 1), and then you can cancel out (x + 1) from both sides. You're left with (x+3)/(2x+3) = 1 if you then divide both sides by (2x + 3)

How do you go about factoring 2x^2 + 5x + 3 anyway? That is the part I'm confused About.
 
Factoring is just one of those things you just "see" after doing a lot of problems. There's no "step by step" method per say, but basically I look at the 2x^2 and 3, and then I try to think of ways of combining them to bet the 5x in the middle. Of course, 2x^2 can be broken into 2x times x, and 3 is broken into 3 times 1. I see that I can multiply 3 by x, resulting in 3x, leaving 1 times 2x. Add them together, and you get 5x! You just need to do a couple of problems to get the hang of factoring.
 
Originally posted by: TMTCC
Factoring is just one of those things you just "see" after doing a lot of problems. There's no "step by step" method per say, but basically I look at the 2x^2 and 3, and then I try to think of ways of combining them to bet the 5x in the middle. Of course, 2x^2 can be broken into 2x times x, and 3 is broken into 3 times 1. I see that I can multiply 3 by x, resulting in 3x, leaving 1 times 2x. Add them together, and you get 5x! You just need to do a couple of problems to get the hang of factoring.

Thanks, I guess with time I'll start to get it. I'm in an environment right now in which I have many distractions going on at once. I'm usually at my school's cafeteria but today I'm at home because I needed to do some things online. Of course having the internet near is not the greatest study tool available. Thanks again.
 
Back
Top