Question for MichaelD

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RaynorWolfcastle

Diamond Member
Feb 8, 2001
8,968
16
81
"Joe has nine apples. Cindy is a fast locomotive. If Joe tells Cindy he wants to hit it at 90mph, how many hours will it take until Pedro cuts the plexiglass?"

Are you crying like a little girl yet? If so, :camera:s, please

Reference for the clueless
 
Colt45

Colt45

Lifer
Apr 18, 2001
19,720
1
0
i dont know the background to this, but i find the question funny as hell :)
 
vi edit

vi edit

Elite Member
Super Moderator
Oct 28, 1999
62,484
8,345
126
Originally posted by: sharkeeper
ROFL...

Sorry I read the first sentence as "Joe has nine nipples".

Cheers!
Click to expand...

Same here. :confused:
 
MichaelD

MichaelD

Lifer
Jan 16, 2001
31,528
3
76
Sorry I'm late to my own roasting; I was busy taking care of my real life.

Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.

Oh...I digressed...you were saying something, RaynorWolfcastle?

 
MichaelD

MichaelD

Lifer
Jan 16, 2001
31,528
3
76
Um...is it me, or is this thread based on the fact that none of you can actually SEE what you're reading? "Nipples" was never mentioned by yours truly. You all have dirty minds. Shame on you!
 
R

RaynorWolfcastle

Diamond Member
Feb 8, 2001
8,968
16
81
Originally posted by: MichaelD
Sorry I'm late to my own roasting; I was busy taking care of my real life.
Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.
Oh...I digressed...you were saying something, RaynorWolfcastle?
Click to expand...
Well if it make you feel any better, I just finished solving a problem, the answer to which is
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)

That solution makes baby Jesus cry.
 
ThePresence

ThePresence

Elite Member
Nov 19, 2001
27,727
16
81
Originally posted by: RaynorWolfcastle
Originally posted by: MichaelD
Sorry I'm late to my own roasting; I was busy taking care of my real life.
Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.
Oh...I digressed...you were saying something, RaynorWolfcastle?
Click to expand...
Well if it make you feel any better, I just finished solving a problem, the answer to which is
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)

That solution makes baby Jesus cry.
Click to expand...

MichaelD = Baby Jesus?! :confused:
 
nakedfrog

nakedfrog

No Lifer
Apr 3, 2001
62,813
19,011
136
Originally posted by: ThePresence
Originally posted by: RaynorWolfcastle
Originally posted by: MichaelD
Sorry I'm late to my own roasting; I was busy taking care of my real life.
Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.
Oh...I digressed...you were saying something, RaynorWolfcastle?
Click to expand...
Well if it make you feel any better, I just finished solving a problem, the answer to which is
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)

That solution makes baby Jesus cry.
Click to expand...

MichaelD = Baby Jesus?! :confused:
Click to expand...


Now I'm crying.
 

Originally posted by: RaynorWolfcastle
Originally posted by: MichaelD
Sorry I'm late to my own roasting; I was busy taking care of my real life.
Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.
Oh...I digressed...you were saying something, RaynorWolfcastle?
Click to expand...
Well if it make you feel any better, I just finished solving a problem, the answer to which is
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)

That solution makes baby Jesus cry.
Click to expand...

That looks incredibly boring. Will that equation make my cd player work?

 
ThePresence

ThePresence

Elite Member
Nov 19, 2001
27,727
16
81
Originally posted by: RaynorWolfcastle
Originally posted by: MichaelD
Sorry I'm late to my own roasting; I was busy taking care of my real life.
Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.
Oh...I digressed...you were saying something, RaynorWolfcastle?
Click to expand...
Well if it make you feel any better, I just finished solving a problem, the answer to which is
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)

That solution makes baby Jesus cry.
Click to expand...

Will Hunting?? Is that you?
 
R

RaynorWolfcastle

Diamond Member
Feb 8, 2001
8,968
16
81
Originally posted by: SampSon
Originally posted by: RaynorWolfcastle
Originally posted by: MichaelD
Sorry I'm late to my own roasting; I was busy taking care of my real life.
Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.
Oh...I digressed...you were saying something, RaynorWolfcastle?
Click to expand...
Well if it make you feel any better, I just finished solving a problem, the answer to which is
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)
That solution makes baby Jesus cry.
Click to expand...

That looks incredibly boring. Will that equation make my cd player work?
Click to expand...

Possibly, it's an equation to minimize noise in a low noise receiver. More practically however, it's something that might be applied to cell phone or WiFi design.

Nobody actually solves an equation like that in the workplace though, you'd usually use a simulator to do it for you but our TA feels we should see what the solution looks like at least once in our lives. :roll: Yeah, whatever.
 
MartyMcFly3

MartyMcFly3

Lifer
Jan 18, 2003
11,436
29
91
www.youtube.com
Originally posted by: RaynorWolfcastle
Originally posted by: SampSon
Originally posted by: RaynorWolfcastle
Originally posted by: MichaelD
Sorry I'm late to my own roasting; I was busy taking care of my real life.
Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.
Oh...I digressed...you were saying something, RaynorWolfcastle?
Click to expand...
Well if it make you feel any better, I just finished solving a problem, the answer to which is
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)
That solution makes baby Jesus cry.
Click to expand...

That looks incredibly boring. Will that equation make my cd player work?
Click to expand...

Possibly, it's an equation to minimize noise in a low noise receiver. More practically however, it's something that might be applied to cell phone or WiFi design.

Nobody actually solves an equation like that in the workplace though, you'd usually use a simulator to do it for you but our TA feels we should see what the solution looks like at least once in our lives. :roll: Yeah, whatever.
Click to expand...


YGPM on something completely unrelated
 
S

sharkeeper

Lifer
Jan 13, 2001
10,886
2
0
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)
Click to expand...


The forums need an <insert symbol> function for this kind of stuff!

Cheers!
 
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