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Question for MichaelD

Sorry I'm late to my own roasting; I was busy taking care of my real life.

Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.

Oh...I digressed...you were saying something, RaynorWolfcastle?

 
Um...is it me, or is this thread based on the fact that none of you can actually SEE what you're reading? "Nipples" was never mentioned by yours truly. You all have dirty minds. Shame on you!
 
Originally posted by: MichaelD
Sorry I'm late to my own roasting; I was busy taking care of my real life.
Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.
Oh...I digressed...you were saying something, RaynorWolfcastle?
Click to expand...
Well if it make you feel any better, I just finished solving a problem, the answer to which is
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)

That solution makes baby Jesus cry.
 
Originally posted by: RaynorWolfcastle
Originally posted by: MichaelD
Sorry I'm late to my own roasting; I was busy taking care of my real life.
Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.
Oh...I digressed...you were saying something, RaynorWolfcastle?
Click to expand...
Well if it make you feel any better, I just finished solving a problem, the answer to which is
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)

That solution makes baby Jesus cry.
Click to expand...

MichaelD = Baby Jesus?! 😕
 
Originally posted by: ThePresence
Originally posted by: RaynorWolfcastle
Originally posted by: MichaelD
Sorry I'm late to my own roasting; I was busy taking care of my real life.
Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.
Oh...I digressed...you were saying something, RaynorWolfcastle?
Click to expand...
Well if it make you feel any better, I just finished solving a problem, the answer to which is
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)

That solution makes baby Jesus cry.
Click to expand...

MichaelD = Baby Jesus?! 😕
Click to expand...


Now I'm crying.
 
Originally posted by: RaynorWolfcastle
Originally posted by: MichaelD
Sorry I'm late to my own roasting; I was busy taking care of my real life.
Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.
Oh...I digressed...you were saying something, RaynorWolfcastle?
Click to expand...
Well if it make you feel any better, I just finished solving a problem, the answer to which is
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)

That solution makes baby Jesus cry.
Click to expand...

That looks incredibly boring. Will that equation make my cd player work?

 
Originally posted by: RaynorWolfcastle
Originally posted by: MichaelD
Sorry I'm late to my own roasting; I was busy taking care of my real life.
Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.
Oh...I digressed...you were saying something, RaynorWolfcastle?
Click to expand...
Well if it make you feel any better, I just finished solving a problem, the answer to which is
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)

That solution makes baby Jesus cry.
Click to expand...

Will Hunting?? Is that you?
 
Originally posted by: SampSon
Originally posted by: RaynorWolfcastle
Originally posted by: MichaelD
Sorry I'm late to my own roasting; I was busy taking care of my real life.
Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.
Oh...I digressed...you were saying something, RaynorWolfcastle?
Click to expand...
Well if it make you feel any better, I just finished solving a problem, the answer to which is
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)
That solution makes baby Jesus cry.
Click to expand...

That looks incredibly boring. Will that equation make my cd player work?
Click to expand...

Possibly, it's an equation to minimize noise in a low noise receiver. More practically however, it's something that might be applied to cell phone or WiFi design.

Nobody actually solves an equation like that in the workplace though, you'd usually use a simulator to do it for you but our TA feels we should see what the solution looks like at least once in our lives. :roll: Yeah, whatever.
 
Originally posted by: RaynorWolfcastle
Originally posted by: SampSon
Originally posted by: RaynorWolfcastle
Originally posted by: MichaelD
Sorry I'm late to my own roasting; I was busy taking care of my real life.
Um...no I'm not sobbing ATM. Luckily my choice of careers places value on real-world experience and not the ability to calculate the theoretical value of some XYZ unknown...in a vacuum...on Mars...on Feb 29th of a leap year...while listening to Dark Side of the Moon...with blacklights on....while inhaling Magnesium Phosphate fumes.
Oh...I digressed...you were saying something, RaynorWolfcastle?
Click to expand...
Well if it make you feel any better, I just finished solving a problem, the answer to which is
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)
That solution makes baby Jesus cry.
Click to expand...

That looks incredibly boring. Will that equation make my cd player work?
Click to expand...

Possibly, it's an equation to minimize noise in a low noise receiver. More practically however, it's something that might be applied to cell phone or WiFi design.

Nobody actually solves an equation like that in the workplace though, you'd usually use a simulator to do it for you but our TA feels we should see what the solution looks like at least once in our lives. :roll: Yeah, whatever.
Click to expand...


YGPM on something completely unrelated
 
R[c] = -r[e]^2*k*T*r[o1]^2*(R^2-r[pi]^2)/(-r[b1]*r[pi]^2*k*T*r[o1]^2+ r[e]^2*r[b2]*R^2*k*T-r[e]^2*r[b2]*k*T*r[pi]^2+ r[e]^2*q*I[c]*R^2*r[o1]^2-r[e]^2*q*I[c]*r[o1]^2*r[pi]^2)
Click to expand...


The forums need an <insert symbol> function for this kind of stuff!

Cheers!
 
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