Question about matrices

johnjbruin

Diamond Member
Jul 17, 2001
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Have been thinking about this way too long, cant come up with it
If you have a matrix A = [a1,a2,...,ak]
where [a1,a2,...,ak] are linearly independent column vectors
and let B = At X A

here At means A transpose

then how do you prove that the column vectors of the matrix B are also linearly independent?
 

Maetryx

Diamond Member
Jan 18, 2001
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God dang. Try the highly technical forum. I even *took* linear algebra and don't have one clue about your problem. Mid nineties are getting farther and farther away....
 

johnjbruin

Diamond Member
Jul 17, 2001
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<< God dang. Try the highly technical forum. I even *took* linear algebra and don't have one clue about your problem. Mid nineties are getting farther and farther away.... >>


yeah i took the linear algebra class also
but this is for a numerical analysis class

I spent a lot of time trying stuff, just couldnt work it out
Come on guys, need some help here.:)
 
Jul 12, 2001
10,142
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<< lol, looks like someone else is trying to do their ee103 hw too. :D >>



dunno about ee103 HW, but my ee113 HW is being a pain in the arse...gonna be long night
 

johnjbruin

Diamond Member
Jul 17, 2001
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<< lol, looks like someone else is trying to do their ee103 hw too. :D >>


yup
you got that right
 
Feb 9, 2000
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I think you are talking about square matrices, right?

"column vectors of A are linearly independent" is equivalent to det[A] != 0

det[At] = det[A]
det(B] = det[At] * det[A] = (det[A])^2 != 0

So the column vectors of the matrix B are also linearly independent.
 

wiggyryder

Member
May 25, 2001
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Step by step...

1. Get At.
2. Multiply At by A to get B.
3. Set [B|0].
4. Use reduce row echelon on B.
5. If you get trivial solutions, then B is linearly independent.
 

johnjbruin

Diamond Member
Jul 17, 2001
4,401
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<< Step by step...

1. Get At.
2. Multiply At by A to get B.
3. Set [B|0].
4. Use reduce row echelon on B.
5. If you get trivial solutions, then B is linearly independent.
>>


This is not for a specific matrix. Need a general solution for all matrices A.
 

SpecialEd

Platinum Member
Jul 18, 2001
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Ahhh... i love alegbra... been out of school for more than a year so I can't help you... but this thread definitely brings me back to the days of college...