first you gotta think about the permutations
if dice 1 is a 1 then what numbers can dice 2 be in order for it to be a multiple of 3?
1: 2, 5
2: 1, 4
3: 3
so we have 5 possible pairs, and you just divide that by how many possible pairs there can be, which is 36, so 5/36??? not sure, haha