• We should now be fully online following an overnight outage. Apologies for any inconvenience, we do not expect there to be any further issues.

probability question

cain

Banned
Aug 1, 2003
2,512
0
0
for my econometrics class, i have to solve such a problem. i know the answer as it is intuitional, hopefully one of you will be able to offer me a solution.

A customer orders a steak in a restaurant. The waiter brings three plates numbered 1, 2
and 3. Each plate has a steak. The waiter tells the person that one of the steaks is safe to
eat, but the other two steaks are tainted with mad-cow disease. The waiter asks the person
to choose a plate. The person randomly picks plate number 2. The waiter then says to the
customer ?according to restaurant policy, I cannot tell you whether the plate you have chosen
has safe meat or tainted meat, however you and I know that at least one of the plates you did
not choose has tainted meat. The famous-chef would like you to know that plate number 3
has tainted meat.?The waiter snaps his ?ngers and plate 3 is sent back to the kitchen to be
ground up and added to the tofu burgers. At this point the customer is getting a little freaked
out and decides to walk out of the restaurant. But, as the customer tries to stand up, the
waiter takes out a gun and demands that the customer try at least one bite of famous-chef?s?
wonderful steak.

Which steak should the customer try: plate 1 or plate 2? After eating the steak, what is
probability that the customer will become sick in 10 years from mad-cow disease? (You may
assume that if the customer eats tainted steak, the customer will get mad-cow disease in 10
years with probability one).
 

MacBaine

Banned
Aug 23, 2001
9,999
0
0
He should choose the other plate, as initially he has a 1/3 chance of winning by choosing the first plate, whereas after the third plate is removed, he will have a 1/2 chance of choosing the winning plate. It's more complicated than that but that's a simple explanation
 

cain

Banned
Aug 1, 2003
2,512
0
0
Originally posted by: MacBaine
He should choose the other plate, as initially he has a 1/3 chance of winning by choosing the first plate, whereas after the third plate is removed, he will have a 1/2 chance of choosing the winning plate. It's more complicated than that but that's a simple explanation

thats the faulty solution, good try though. you need to use bayes theorem probably, i just cant remember how to do it
 

furie27

Senior member
Apr 22, 2004
684
0
0
I think you can use the "Let's make a deal" solution to this. Don't have the proof handy, but conditional probabilities will get you to it.