Poll: How many Unique Digits are in your SS#?

Page 2 - Seeking answers? Join the AnandTech community: where nearly half-a-million members share solutions and discuss the latest tech.

KK

Lifer
Jan 2, 2001
15,903
4
81
My SS# is 205-43-3934, so that would be 4 unique digits?

KK
 

Nitemare

Lifer
Feb 8, 2001
35,461
4
81
Originally posted by: KK
My SS# is 205-43-3934, so that would be 4 unique digits?

KK

No way...my housekeeper and 2 of my landscapers have that same SS#...
 

DeafeningSilence

Golden Member
Jul 2, 2002
1,874
1
0
Originally posted by: dman6666
My reasoning:

9 Digits times 9 locations = 81 possible. (you can actually rule a few of these out for SS#'s because they haven't gotten up past 7 for the first digit, so that takes away a few 'real' combinations). But assuming the maximum...

And there are 10 digits * 81 (possible combinations with 9 spots) 81 * 10 = 810.

I could be very wrong. [edit]I don't think so though. I think some of the 9 voters lied. Otherwise we'd have a nice bell curve and we don't! Take that! :D [/edit]

It's been a while since I had stats too. But wouldn't it be this? 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 = 3628800.
 

Nitemare

Lifer
Feb 8, 2001
35,461
4
81
Originally posted by: DeafeningSilence
1 - All the same .... 6 (votes)

Amazing! There are only 10 possible SSNs that consist of a single digit repeated... and 6 of them post here at AT! :D

ambiguous poll..

could have 112-23-3991

and have no unique numbers
 

dman

Diamond Member
Nov 2, 1999
9,110
0
76
Ah, I guess it's open to interpretation.. in your example: 112-23-3991

1,2,3,9 are unique. thus You'd pick 4 in the poll. That was the intent.

I think the majority of people got that, based on the curve.
 

DeafeningSilence

Golden Member
Jul 2, 2002
1,874
1
0
Originally posted by: dman6666
Originally posted by: DeafeningSilence
Originally posted by: dman6666
My reasoning:

9 Digits times 9 locations = 81 possible. (you can actually rule a few of these out for SS#'s because they haven't gotten up past 7 for the first digit, so that takes away a few 'real' combinations). But assuming the maximum...

And there are 10 digits * 81 (possible combinations with 9 spots) 81 * 10 = 810.

I could be very wrong. [edit]I don't think so though. I think some of the 9 voters lied. Otherwise we'd have a nice bell curve and we don't! Take that! :D [/edit]

It's been a while since I had stats too. But wouldn't it be this? 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 = 3628800.
I believe that is for ALL combinations. In a lottery analogy, there would be 90 balls numbered 0..9, and 9 slots.


In the case I'm talking about, there are 10 balls (0..9) and 9 slots... so you can't have any repeating #'s.

123456789
012345678
901234567
890123456
789012345
678901234
567890123
456789012
345678901
234567890

are the 10 possible unique number sets. And each of those sets can be arranged 9x9 times = 81. So The total should be 10x81 = 810. And like the case where the folks picked #1 too many times, I think 10 people having non-repeating #'s in their ss# is an unusually large amount to be represented on ATOT. Based on the curve, at least 3 people lied so far.

I actually don't think my solution was all possible combinations. To get all possible combinations (duplication allowed), it would be 10x10x10x10x10x10x10x10x10 = 10^9. In my equation, there are 10 choices for the first digit, leaving 9 choices for the second digit, 8 for the third, and so forth. This would prevent duplication of any number.