Physics Question

[AgaBoogaBoo]

I've tried doing this on my own, drew it out, but not clue how to put it "together" into equations.

Problem: You are a pilot on an aircraft carrier, now 1450 km at 45 degrees of your position, moving at 56km/h due east. The wind is blowing from the south at 72 km/h. Calculate the heading and air speed needed to reach the carrier 2.5 hours after you take off.

Hint: Draw a displacement vector diagram

 

[Wheatmaster]

use components!

 

[Tweak155]

use vectors...the wind is 72km north, and the first thing you need to do is find where its gonna be in 2.5 hrs, so just 2.5*56 will give you the distance you need to go in 2.5 hrs, that should get you started

EDIT:

thats 2.5*56 + the horizontal vector already included

 

[jagec]

How can you be a pilot ON an aircraft carrier, if it's currently 1450 km away?😛

 

[imported_Sasha]

Use the cartesian coordinates (x,y) and decompose vectors into their X and Y component vectors. Now, you know where you are and where you have to be, treat the case as two individual one-dimension displacement d = dº + vt + at^2 noting that 'v' is also a vector and needs to be decomposed into its constituent X and Y velocity components.

 

[AgaBoogaBoo]

Originally posted by: Tweak155
use vectors...the wind is 72km north, and the first thing you need to do is find where its gonna be in 2.5 hrs, so just 2.5*56 will give you the distance you need to go in 2.5 hrs, that should get you started

EDIT:

thats 2.5*56 + the horizontal vector already included

Ok, that would be 1590. I know the answer is 580 km/h @ 53 degrees east of north

I tried calculating based on knowing I need to travel 1590 km and wind going north @ 72 km/h

I put that into a triangle and use the pythagorean thereom, got a wrong answer. What am I doing wrong?

 

[AgaBoogaBoo]

^

 

[AgaBoogaBoo]

Come on AT! You're slackin tonight!

 

[AgaBoogaBoo]

Wow.... no help yet...