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Physics Problem: Bernoulli's Equation

Riddleman

Senior member
62. In a very large closed tank, the absolute pressure of the air above the water is 6.01x10^5 Pa. The water leaves the bo0ttom of the tank through a nozzle that is directed straight upward. The opening of the nozzle is 4.00 m below the surface of the water. (a)Find the speed at which the water leaves the nozzle. (b) Ignoring air resistance and viscous effects, determine the height to which the water rises.

I got part A, but don't know if its right since it doesnt make sense in relation to part b. Thanks for checking this out.

Chapter 11 prob 62
 
The way they teach introductory phyiscs in college is a joke. Is it possible to blaze through 25 chapters in a term?

The average on my 2nd midterm for physics I was a 22/100. I got a 51😀


Noone ever retains anything, just bs on the test and you'll be good to go.
 
Originally posted by: Gl4di4tor
Originally posted by: ArmenK
The nozzle is directed upward, so there is a bend in the nozzle and it points up.

Yeah but still, how could the water rise? is my answer for part A right?

Treat part B as simple projectile motion using the velocity you got for part A.
 
you can use the general bernoulli equation and cancel out the stuff you don't need, same for the first part. It looks like you are just using a given equation which is a simplified version of this.

p/gamma+v^2/2g+z=p2/gamma+v2^2/2g+z2

gamma is specific gravity of water (9.8 kg/m^3 I believe)
p=pressure
z=height from reference

Just use this equation from the different points in question. I could explain more but I don't have time right now. Hope this helps
 
Originally posted by: Armitage
Originally posted by: Gl4di4tor
Originally posted by: ArmenK
The nozzle is directed upward, so there is a bend in the nozzle and it points up.

Yeah but still, how could the water rise? is my answer for part A right?

Treat part B as simple projectile motion using the velocity you got for part A.

And if you're industrious, you can see that Bernoulli's equation can also be used to find the height (hint, it reduces to the same equation as the projectile motion equation).
 
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