Physics/Calculus help

[JohnCU]

x = 2.00 + 3.00t - t^2

x = position in meters, t = seconds

v = dx/dt
That's a derivative, right? So v = 3.00 - 2.00t

But, I've just started Calculus so I have no idea how they got to that point. My TI-89 does derivatives, I just need to know how to put that up there in... like, I take the derivative of x and divide it by the derivative of t?? Need the actual steps.

Thanks.

 

[Oscar1613]

dx/dt just means the derivative of x with respect to t, not derivative of x divided by derivative of t.

theres a lot of proofs behind it that you'll go through in calculus, but basically the derivative of a power function y(x) = Ax^B, where A and B are constants, is
dy/dx = B*Ax^(B-1).

so in this case, x(t) = 2 + 3t - t^2
and you can just skip to
dx/dt = 3 - 2t

 

[JohnCU]

Thank you.