Only odd number of Nash Equilibriums

UncleWai

Diamond Member
Oct 23, 2001
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In this simultaneous case

L R
U (0,0) (0,0)

D (10,10) (0,0)

Aren't there two pure NE in LD and UR?

If that's the case, shouldn't there be a mixed strategy in between?
If I find that, alpha and beta (the probability of each player) are both zero. That's the same as UR, no?
So where's the odd number of NE?