new question, calc. voltage drop

[MikeMike]

so it would be

xxxAmps/(xxxElectrons * their charge) = V

 

[globalcitizen]

Originally posted by: nourdmrolNMT1
so it would be

xxxAmps/(xxxElectrons * their charge) = V

Yes

 

[TheLonelyPhoenix]

Originally posted by: nourdmrolNMT1
so it would be

xxxAmps/(xxxElectrons * their charge) = V

Amps is a measure of current, not energy.

 

[MikeMike]

ok, now given flow rate in xC/min and xJ of heat dissapated in xSeconds, how do i find the voltage drop across the circuit?

 

[PurdueRy]

probably...Joules of heat/(flow rate x time)

 

[MikeMike]

Ry, ygpm