New Math problem with 100% less 12 year old.

[thescreensavers]

My trig class was a year ago so I forgot this shiz

Find the rectangular coordinates of the point that has polar coordinates (2, 11pi/6)

So its Polar to Rectangular

11pi/6 is 330 degrees

(2,330)

X= r cos 330
Y= r sin 330



r = square root y^2+x^2

So its 2^2 + 330^2 or 11pi/6^2?

sqrt 330^2 + 2^2 = 2 sqrt 27226

X =-327.1016184
Y= -43.68673994

sqrt 11pi/6^2 + 2^2 = sqrt 4+11pi/36

X=-2.207489256
Y=-0.2948258389

What do I put down for r?

 

[spidey07]

You're 12, aren't you?

 

[MagnusTheBrewer]

Correct and yes, you are going nuts. Where'd the pie go? 🙂

 

[Crusty]

You're 12, aren't you?

I hope so, this is basic algebra!

 

[Crono]

You have to do operations to both sides so that h is the only variable left (remaining) on the right side.

No, I won't solve it for you 😀 But yes, your answer is the right idea.

 

[spidey07]

I hope so, this is basic algebra!

You'd be surprised at what they're teaching kids these days. Not to brag but we were taught this around age 12.

 

[Freshgeardude]

h = v/ 3r^2

 

[Gigantopithecus]

You'd be surprised at what they're teaching kids these days. Not to brag but we were taught this around age 12.

When do they teach us not to be assholes on the internet simply because we're anonymous? I'm 29 and they still haven't gotten to that.

 

[thescreensavers]

You have to do operations to both sides so that h is the only variable left (remaining) on the right side.

No, I won't solve it for you 😀 But yes, your answer is the right idea.

ah thanks

I forgot to ad a Pi in there, I fixed the OP

so it will be

h= V*pi/3r^2 ?

 

[RapidSnail]

h = v/ 3r^2

Actually, h = 3v/(pi*r^2)

 

[Crono]

Actually, h = 3v/(pi*r^2)

That.

And not that I would use it for something this simple, but couldn't Wolfram (and Hart 😛) solve this?

 

[Freshgeardude]

Actually, h = 3v/(pi*r^2)

why? divide both sides by 1/3 pi r^2

you are left with 1h, the other side is 1 v/3 pi r^2

 

[Freshgeardude]

im confuzzled

 

[Hacp]

Please tell me this isn't for a business math course. Lol.

 

[herm0016]

that would leave you with v/1/3*1/pi*r^2 the 1/3 is under the v not the 3


fresh gear must be 11, i know we learned fractions before that.

 

[thescreensavers]

OP updated with 100 percent less 12 year old problem.

What do I put down for r?

 

[TuxDave]

OP updated with 100 percent less 12 year old problem.

What do I put down for r?

When you see the polar coordinates of (2, 11pi/6), don't you ask yourself, what's the 2 for?

Ah, I see your misunderstanding. Polar coordinates is (radius, angle), rectangular coordinates is (x,y). You shouldn't be using 2 for x and 11pi/6 for y since it's not rectangular coordinates

 

[thescreensavers]

^ I am not sure

The Formula I see for r is sqrt y^2+ x^2

Whats the 2 for?

2 is the radial coordinate and 11pi/6 is the Angular coordinate.

r is the distance from the origin. so would that make it the radius?

so it would be 2cos330 2sin330?

 

[TuxDave]

^ I am not sure

The Formula I see for r is sqrt y^2+ x^2

Whats the 2 for?

2 is the radial coordinate and 11pi/6 is the Angular coordinate.

r is the distance from the origin. so would that make it the radius?

so it would be 2cos330 2sin330?

yes

 

[Rezag3000]

^ I am not sure

The Formula I see for r is sqrt y^2+ x^2

Whats the 2 for?

2 is the radial coordinate and 11pi/6 is the Angular coordinate.

r is the distance from the origin. so would that make it the radius?

so it would be 2cos330 2sin330?

don't worry, I'm here.

The formula that you have, "r is sqrt y^2+ x^2" is for finding r when you are given rectangular coordinates (x,y). When you are given polar coordinates, you are by definition given r as well. In your case, r=2.

 

[nonameo]

Think about spinning bowls and orange juice. both of them have to do with circles, and so therefore god exists.

 

[JPS35]

I like apple pie

 

[Ken g6]

Find the rectangular coordinates of the point that has polar coordinates (2, 11pi/6)

Polar coordinates are of the form (r, &#952😉

X= r cos 330
Y= r sin 330

You're on the right track there. 🙂

 

[DrPizza]

You use the formula x²+y²=r² when you're switching from rectangular coordinates to polar coordinates; not the other way.

 

[thescreensavers]

^ yea I got that.

Thanks for the help guys, I was way over thinking it 😀