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Need math help

Simplify? What do you mean simplify? Those are as simple as they get. At least I can't figure out anything else to do with them.
 
Use the first co-function identity given in the URL that syringer provided.

It looks like:

sin(pi/2 - theta) = cos theta.

I am guessing that the answer to the first one is along the lines of "cos x".
 
For example..

since sin (y-x) = sin x*cos y - cos x * sin y
sin(pi/2 - x)
= sin(pi/2)cos(x) - cos(pi/2) * sin x
sin pi/2 = 1
cos pi/2 = 0

So that is 1 * cos (x) - 0 * sin x
= cos(x)
 
You also need to remember that the sine and cosine functions are 2-Pi-periodic-- which means you can safely remove 2*Pi from any argument to a sine or cosine function without changing its value...

In other words:

sin(5*Pi / 2 - x) = sin( [5*Pi / 2 - x] - 2*Pi) = sin(Pi/2 - x), and similiarly
cos(5*Pi/ 2 - x) = cos(Pi/2 - x)


 
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