Need help with easy math problem.

[SP33Demon]

Ok this is really simple, need to know how many numbers would be missing from 0 to 999 counting by 3, for example 0,3,6,9,12. It's been awhile since I did this and I forget the equation (15 years since basic math haha).

Thanks.

 

[MiLLeRTiMe]

ummm unless im looking at it wrong would it just be 666?

999/3 = 333

999-333=666

hope this helps..

l8rz,
~miller

edit* add 1 to the anwser for zero

 

[Kyteland]

334

There are exactly 999 numbers from 1-999 so there are 333 number in that range regardless of position. Then you just add the 0 on to that to get 334.

Edit: oops, misread. 1000-334 = 666 ( :evil: )

 

[SP33Demon]

Thanks guys! I got the same answer [(999/3) + 1], but just wanted to be 100% since this has to be perfect for some code I'm doing.

~Rob