Originally posted by: coder1
So I could set k as any value and the results would be the same?
Originally posted by: coder1
So I could set k as any value and the results would be the same?
Originally posted by: GreatBarracuda
Originally posted by: coder1
So I could set k as any value and the results would be the same?
Ok. Since you know that x-2 is a factor of the expression, substituing x = 2 in the expression would make it equal to zero. So doing that will give you:
8k - 4 - 10k + 12 = 0
2k = 8
k = 4
Voila!
Originally posted by: halik
algebra.... thats one of those things you forget after surface and vector integrals. All of my friends agree that after taking years of calc, you have no idea how to do stuff like that
Originally posted by: cchen
Originally posted by: halik
algebra.... thats one of those things you forget after surface and vector integrals. All of my friends agree that after taking years of calc, you have no idea how to do stuff like that
actually, its pretty sad if you've taken calc and can't figure that one out
Originally posted by: saxguy
Originally posted by: cchen
Originally posted by: halik
algebra.... thats one of those things you forget after surface and vector integrals. All of my friends agree that after taking years of calc, you have no idea how to do stuff like that
actually, its pretty sad if you've taken calc and can't figure that one out
yes. you should be able to do that in your head.
Originally posted by: GreatBarracuda
Originally posted by: saxguy
Originally posted by: cchen
Originally posted by: halik
algebra.... thats one of those things you forget after surface and vector integrals. All of my friends agree that after taking years of calc, you have no idea how to do stuff like that
actually, its pretty sad if you've taken calc and can't figure that one out
yes. you should be able to do that in your head.
Sometimes it's the way the question is set up. I don't think he meant Algebra in general, because that's sad![]()
