Need help deriving cotx/sinx

[AgaBoogaBoo]

I need help deriving cotx/sinx

Is the quotient rule along with the chain rule the only way to solve this? Substituting cosx/sinx for cotx won't help incase that's what you're trying by the way, doesn't cancel anything out

 

[AgaBoogaBoo]

bump? 😛

 

[reverend boltron]

shouldn't it just be: ((sin(x))(csc^2(x))-(cot(x)(cos(x))/(sin^2x)

 

[reverend boltron]

I don't think you need to use the chain rule.. If you leave cotx as it is.. .. remember this way for deriving the trig functions..

if someone's sitting next to you, and you say "psst! how do you derive the trig functions?" take that "sst" from psst..
Sec Sec Tan .. and take their counterparts..
Csc Csc Cot

so if you want to derive Sec, it's secX*tanX .. and if you want to derive tanX its secX*secX .. or sec^2(x) .. just go in whatever direction you need to..
you can even follow an arrow
Sec-->Sec <--Tan
Csc-->Csc <--Cot .. so if you want Cot, follow the arrow.. you get Csc(x)*Csc(x) .. get it?