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Need help 3d modeling a part

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radtechtips

Senior member
I have no clue what to do to get this. I have no idea what command to use, please help!

Its essentially a rectangular prism that ends in a circle. Do i need to use a cone or something? I use Inventor 2014 Pro if that helps...

kOmXlGl.png


dMsjwXK.png


VM22v4k.png


http://imgur.com/a/h2Ibe
 
What part can't you model?
The rounded part is just a revolved cutout.

Do you want me to model it for you? It would take about 5 min.
 
I'm thinking a sphere merged with a rectangular prism, then you slice the top off the sphere.
Then again, I still model with play doh.

Here's to Mr. Kumfer and 7th grade industrial arts. I can still hear him bellow, "Orthographic draaaawingggggg."
 
It doesn't give a radius dimension for the rounded part, so maybe it is a free formed curve.
I used a radius value of 3.0" and it looks almost identical.

o3j8Cvb.jpg
 
Did you just sketch the cutout out on a center plane and revolve it?
Yes, pretty much.
It helps if you create a 45 deg. plane that goes through the corners of the part.
You can then create the cutout sketch on that plane.
That sketch will have the 1.3125 and .4375 dims and you will need to make the curved portion a 3.0" radius.
 
Is that radius really necessary? It limits your manufacturing options (e.g. it's a bitch to make this on a manual mill).

My guess is that the handle pivots around an external axis, and when tightened, aligns with a spherical "counterbore" so that the handle is always in the same spot when tight. But you don't really need this, do you?
 
Is that radius really necessary? It limits your manufacturing options (e.g. it's a bitch to make this on a manual mill).

My guess is that the handle pivots around an external axis, and when tightened, aligns with a spherical "counterbore" so that the handle is always in the same spot when tight. But you don't really need this, do you?

My guess is that its a homework problem for a CAD 101 class.
 
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