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My head hurts from this.

TridenT

Lifer
Sep 4, 2006
16,800
45
91
omfgpain.jpg


D:

I don't even...

I've been trying to wrap my brain around it, but it's kinda outta my league I guess.

90ohm + 1/(1/330 + 1/(250+1200+650+675+50) + 1/(75+30+225+47+200+62)) is my best guess...

But I think I am way off.
 
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IronWing

No Lifer
Jul 20, 2001
72,903
34,007
136
Homework tip: Go to Radioshack and buy $1.59 worth the resistors and wire and just build the damn thing. Then when you know the answer, try to figure out why it is true.
 

theflyingpig

Banned
Mar 9, 2008
5,616
18
0
Holy shit. You're having a hard time with *that*?! You can't even call yourself a nerd. Jesus. You really are a failure.
 

tatteredpotato

Diamond Member
Jul 23, 2006
3,934
0
76
Dude just break it up into smaller problems. Combine all those on the right in series, then the 1.2k and 650, then combine those two parallel values. Repeat until there's only one value left....
 

Sumguy

Golden Member
Jun 2, 2007
1,409
0
0
WTF? I hope your school started way later than mine. No, scratch that. It HAD to have started later.

OK so look at it this way. You pretty much add the ENTIRE FUCKING RIGHT SIDE up, since they are all in series. Once you do that, you have one Req in parallel with 1.2k and 650 resistors in series. I really hope you know what to do at that point.

After that, you have 4 resistors in series that are all in parallel with the 330 ohm resistor.

If you can't figure it out from there, words can't begin to describe how fucked you are.
 

rcpratt

Lifer
Jul 2, 2009
10,433
110
116
Add all the series up first. Then do the far two right parallel ones (one that you created by adding all 6 series). Then add the result of that to those in series with it (250, 50, 675). Then do that parallel with 330. Then add that to 90.
 

mesthead21

Platinum Member
Jun 5, 2004
2,378
3
0
Do you cry at every homework assignment you get? I've never seen someone without a vagina bitch as much as you.

Fucking jeebus
 

TridenT

Lifer
Sep 4, 2006
16,800
45
91
WTF? I hope your school started way later than mine. No, scratch that. It HAD to have started later.

OK so look at it this way. You pretty much add the ENTIRE FUCKING RIGHT SIDE up, since they are all in series. Once you do that, you have one Req in parallel with 1.2k and 650 resistors in series. I really hope you know what to do at that point.

After that, you have 4 resistors in series that are all in parallel with the 330 ohm resistor.

If you can't figure it out from there, words can't begin to describe how fucked you are.

What? We cover new subjects every week that were completely unrelated to the previous... This week is electrical circuits. We didn't get indepth at all because we did some other shit. :(
 

TridenT

Lifer
Sep 4, 2006
16,800
45
91
90ohm + 1/(1/330 + 1/(250+1200+650+675+50) + 1/(75+30+225+47+200+62)) is my best guess...

But I think I am way off.



So was I right with my guess? because what I've read from your posts it looks somewhat similar.
 

Mr. Pedantic

Diamond Member
Feb 14, 2010
5,027
0
76
I'm no expert at physics, but I can see 3 loops: 420, 2915, and 1704 ohms. You put them together in parallel to get the total resistance...?

EDIT: Ok, that's completely wrong. I got 359.
 
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rcpratt

Lifer
Jul 2, 2009
10,433
110
116
I'm no expert at physics, but I can see 3 loops: 420, 2915, and 1704 ohms. You put them together in parallel to get the total resistance...?
No, that's what he did. You can't add the middle horizontal ones to the middle leg.
 

Sumguy

Golden Member
Jun 2, 2007
1,409
0
0
What? We cover new subjects every week that were completely unrelated to the previous... This week is electrical circuits. We didn't get indepth at all because we did some other shit. :(

Doesn't matter, unless your teacher is terrible at explaining things. Don't worry about making one huge equation, solve little parts of the circuit first.

I'm gonna assume you're taking physics 2. Circuits was the easiest part of both physics classes, except maybe optics.
 

TecHNooB

Diamond Member
Sep 10, 2005
7,458
1
76
for resistors in series:
R_eq = R1 + R2

for resistors in parallel:
R_eq = R1 * R2 / (R1 + R2)