More Alg help.. now we've got something completly different! Thanks for the help, those whove already been here!

[ViperMagic]

Ok, heres the problem:

7x^2-3x-1=0

I can get it down to:

X=2+[sqrt]37
----------------------
14


where do I go from here?
Thanks

 

[b0mbrman]

That's your answer...

 

[HombrePequeno]

and your done

 

[Hoeboy]

no more variables = done. keep in mind that as math gets tougher, the answer isn't always gonna be a simple number. sometimes better to leave it that way than chug at the #.

 

[ViperMagic]

OK, I was sick this day, so could someoen tell me what the heck I'm suposed to do here? Thanks

Factor Each equation to determine whether it containsa quadratic factor. If do, write the quadric factor. If not, write "no"

Solve: x^4 + x^2 -30 = 0

 

[ViperMagic]

^

 

[b0mbrman]

<< OK, I was sick this day, so could someoen tell me what the heck I'm suposed to do here? Thanks

Factor Each equation to determine whether it containsa quadratic factor. If do, write the quadric factor. If not, write "no"

Solve: x^4 + x^2 -30 = 0 >>


Yup...but this time, just use x^2 instead of x

e.g. x^2 = b +- sqrt(b^2-4ac) / 2a

Note, that may not be right at all...just going off memory 🙂

 

[ViperMagic]

What I need to know is:

WTF do I do when a varabile is under a radical?

What do I do when instead of "ax^2+bx+c=0" its like "ax^4+bx^3+c=0"?

 

[Hoeboy]

kinda hard to visualize a problem from typing it out but aren't ya suppose to factor the equation into two different ones? you have a polynomial to the 4th power. you can factor it out to be two polynomial to the 2nd power, which would then be able to stick into a quadratic formula.

 

[Czar]

x= 0.6487 or -0.2201