Math puzzle!

[Freshgeardude]

64 times the difference of two different integers is the same as the difference of their squares. find the sum of the numbers

 

[Demon-Xanth]

42

 

[OdiN]

Originally posted by: Demon-Xanth
42

this

 

[Freshgeardude]

thanks guys, think you could show me how you got the answer?

 

[Born2bwire]

\pi/2

 

[MikeyLSU]

answer is 64

31 and 33 are the numbers

 

[mugs]

0 and 64

 

[silverpig]

64(x-y) = x^2 - y^2

64(x-y) = (x+y)(x-y)

x+y=64 (if x =/= y)

Done.

edit: It is given in the question that the two integers are different, so I don't have to make the (x =/= y) claim.

edit 2: If you allow the numbers to be the same, then 32,32 works as well

 

[Demon-Xanth]

Originally posted by: freshgeardude
thanks guys, think you could show me how you got the answer?

no

 

[udneekgnim]

Originally posted by: freshgeardude
64 times the difference of two different integers is the same as the difference of their squares. find the sum of the numbers

I get 64

64 (64 - 0) = 64^2 - 0^2

think a math wiz would have intuitively seen it, but I had to use algebra =(

good thing my middle school eduction sure came in handy =)

 

[randay]

highschool would have been so much easier if only there was an ATOT back then...

 

[CPA]

eleventybillion.

 

[chuckywang]

Originally posted by: freshgeardude
64 times the difference of two different integers is the same as the difference of their squares. find the sum of the numbers

64 ... and that took me 10 seconds to do in my head.

 

[Injury]

Originally posted by: freshgeardude
thanks guys, think you could show me how you got the answer?

Think you can do your own homework before someone digs up enough information about you to email your teacher/professor/etc?

 

[JDub02]

The answer is Chuck Norris ... because Chuck Norris is never wrong.