MrDingleDangle
Lifer
Originally posted by: newt
Originally posted by: Merkon
Originally posted by: newt
a+b+c+d =3x and a<b<c<d while a,b,c,d are all between 0-9, then a+b+c+d could only be 6, 9, 12, 15, 18, 21, 24, 27, 30 because when a+b+c+d=6, {a,b,c,d) must be {0,1,2,3}, which makes the smallest 3x. When a+b+c+d=30, {a,b,c,d}must be {6,7,8,9}, which makes the largest 3x possible.
When a+b+c+d=6, there's 1 combination
=9, 3 combinations
=12, 9 combinations
=15, 14 combinations
=18, 18 combinations
=21, 14 combinations
=24, 9 combinations
=27, 3 combinations
=30, 1 combinations
so 1+3+9+14+18+14+9+3+1=72 ways to arrange a,b,c and d.
How is it a "possible answer"? what are other possible answers?
Well they are all multiple choice, but if I told you that I would fear you would just make up some crap that has to do with one of the answers.
Math is fun.....the third question is more of logic though
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my g/f is a dork