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Math Problem - 2

J

jeffeh

Banned
( 2x-2 / x^2 )* (x^3 / 4x - 8)

so from here I expanded and cancelled out (x-1) in the first fraction

then combined the two to get

2x^3 / 4x^2-2

from here I'm not sure if the x^3 would cancel out the x^2 on the bottom?
 
Originally posted by: kevinthenerd
Originally posted by: Syringer
Originally posted by: ntdz
Just cross multiply, it's easier to do it that way...
Click to expand...

Are you being serious? You need an equal sign to cross multiply.
Click to expand...

Maybe they're trying to mislead him? I was honestly tempted to do so through a PM. lol
Click to expand...

How would you feel if someone purposely mislead you when you asked for help in one of your EE classes?
 
Would it kill you to use parenthesis? (x^3 / 4x - 8) != (x^3 / (4x - 8))

anyway, you might want to redo your work...there's only one (x-1) term, so you can't cancel.
 
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