Math Probability question...

ZeroNine8

Member
Oct 16, 2003
195
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1 in 5^5, or 1 in 3125. (2 in 3125 if you count reverse alphabetic order)

If that's not right, 1 in 42.
 

Chaotic42

Lifer
Jun 15, 2001
35,380
2,501
126
Originally posted by: Excelsior
Obviously we are assuming that they have different names.

Already tried 1/120

You already tried 1/120?

Already tried what?

The chance that A will sit in the 1st is 1/5. The chance that B will sit in the next seat is 1/4. The chance that C will sit in the next seat is 1/3. The chance that D will sit in the next seat is 1/2.

5*4*3*2=120

Edit: Can they all sit down at the same time?
 

Excelsior

Lifer
May 30, 2002
19,047
18
81
Originally posted by: Chaotic42
Originally posted by: Excelsior
Obviously we are assuming that they have different names.

Already tried 1/120

You already tried 1/120?

Already tried what?

The chance that A will sit in the 1st is 1/5. The chance that B will sit in the next seat is 1/4. The chance that C will sit in the next seat is 1/3. The chance that D will sit in the next seat is 1/2.

5*4*3*2=120

Edit: Can they all sit down at the same time?

No, it IS 120, you are right. The girl wasn't putting it in right. I thought it was 120 too (she was doing decimal form instead of fractions).
 

Chaotic42

Lifer
Jun 15, 2001
35,380
2,501
126
Originally posted by: Excelsior
No, it IS 120, you are right. The girl wasn't putting it in right. I thought it was 120 too (she was doing decimal form instead of fractions).
Ok, cool. I was wondering what I was doing wrong!

:beer:
 

jspeicher

Golden Member
Apr 9, 2003
1,904
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well what if the first guy/girl farts as he/she is sitting down first...and then immediately stands back up?
 

hans007

Lifer
Feb 1, 2000
20,212
18
81
assuming their names are all different its just 5 factorial ways.


i suppose if the chairs are in a row, there are two ways they can sit in order


like

abcde

or edcba


so thats 2/5! 1/60