Math Help

speg

Diamond Member
Apr 30, 2000
3,681
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www.speg.com
I'm going to sound really dumb in a second, but I haven't taken calculus in 4 years and don't have the textbook with me...

1. For each function below, ?nd
?f and D^2(f)

(a) f (x, y) = x^2 + xy^2 - e^y


I know ? is the grad operator, but what is D^2?

:eek:
 

speg

Diamond Member
Apr 30, 2000
3,681
3
76
www.speg.com
I know I've done Calc 3... and this is a "Math for Econ" class, so I haven't been attending most of the classes... it's all pretty easy if only I could understand the question...
 

chronox

Member
Feb 3, 2008
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Could it mean the second derivative of the function f(x,y) via implicit differentiation?
 

frostedflakes

Diamond Member
Mar 1, 2005
7,925
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81
Maybe second derivative of the gradient field? Just a guess, sorry that isn't ringing any bells for me either. :(
 

MaxFusion16

Golden Member
Dec 21, 2001
1,512
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it's asking for the second derivative, but with respect to what?
it doesn't specify what variable to differentiate with respect to, x or y.
 

hypn0tik

Diamond Member
Jul 5, 2005
5,866
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Originally posted by: speg
I'm going to sound really dumb in a second, but I haven't taken calculus in 4 years and don't have the textbook with me...

1. For each function below, ?nd
?f and D^2(f)

(a) f (x, y) = x^2 + xy^2 - e^y


I know ? is the grad operator, but what is D^2?

:eek:

Is D^2 the Laplacian?
 
Aug 10, 2001
10,420
2
0
Originally posted by: hypn0tik
Originally posted by: speg
I'm going to sound really dumb in a second, but I haven't taken calculus in 4 years and don't have the textbook with me...

1. For each function below, ?nd
?f and D^2(f)

(a) f (x, y) = x^2 + xy^2 - e^y


I know ? is the grad operator, but what is D^2?

:eek:

Is D^2 the Laplacian?

You're probably right.

D(f) = ?f = (?f/?x,?f/?y,?f/?z)
D^2(f) = ?²f = ?·?f = (?/?x,?/?y,?/?z)·(?f/?x,?f/?y,?f/?z) = ?²f/?x²+?²f/?y²+?²f/?z²
 

TecHNooB

Diamond Member
Sep 10, 2005
7,458
1
76
Originally posted by: Random Variable
Originally posted by: hypn0tik
Originally posted by: speg
I'm going to sound really dumb in a second, but I haven't taken calculus in 4 years and don't have the textbook with me...

1. For each function below, ?nd
?f and D^2(f)

(a) f (x, y) = x^2 + xy^2 - e^y


I know ? is the grad operator, but what is D^2?

:eek:

Is D^2 the Laplacian?

You're probably right.

D(f) = ?f = (?f/?x,?f/?y,?f/?z)
D^2(f) = ?²f = ?·?f = (?/?x,?/?y,?/?z)·(?f/?x,?f/?y,?f/?z) = ?²f/?x²+?²f/?y²+?²f/?z²

Put those math symbols away!
 

JohnCU

Banned
Dec 9, 2000
16,528
4
0
Originally posted by: Random Variable
Originally posted by: hypn0tik
Originally posted by: speg
I'm going to sound really dumb in a second, but I haven't taken calculus in 4 years and don't have the textbook with me...

1. For each function below, ?nd
?f and D^2(f)

(a) f (x, y) = x^2 + xy^2 - e^y


I know ? is the grad operator, but what is D^2?

:eek:

Is D^2 the Laplacian?

You're probably right.

D(f) = ?f = (?f/?x,?f/?y,?f/?z)
D^2(f) = ?²f = ?·?f = (?/?x,?/?y,?/?z)·(?f/?x,?f/?y,?f/?z) = ?²f/?x²+?²f/?y²+?²f/?z²

i just came

 

chronox

Member
Feb 3, 2008
88
0
0
Originally posted by: JohnCU
Originally posted by: Random Variable
Originally posted by: hypn0tik
Originally posted by: speg
I'm going to sound really dumb in a second, but I haven't taken calculus in 4 years and don't have the textbook with me...

1. For each function below, ?nd
?f and D^2(f)

(a) f (x, y) = x^2 + xy^2 - e^y


I know ? is the grad operator, but what is D^2?

:eek:

Is D^2 the Laplacian?

You're probably right.

D(f) = ?f = (?f/?x,?f/?y,?f/?z)
D^2(f) = ?²f = ?·?f = (?/?x,?/?y,?/?z)·(?f/?x,?f/?y,?f/?z) = ?²f/?x²+?²f/?y²+?²f/?z²

i just came

:laugh: I've been out of school only 1.5yrs and boy, do I miss seeing this stuff.
 

artikk

Diamond Member
Dec 24, 2004
4,172
1
71
Originally posted by: JohnCU
Originally posted by: Random Variable
Originally posted by: hypn0tik
Originally posted by: speg
I'm going to sound really dumb in a second, but I haven't taken calculus in 4 years and don't have the textbook with me...

1. For each function below, ?nd
?f and D^2(f)

(a) f (x, y) = x^2 + xy^2 - e^y


I know ? is the grad operator, but what is D^2?

:eek:

Is D^2 the Laplacian?

You're probably right.

D(f) = ?f = (?f/?x,?f/?y,?f/?z)
D^2(f) = ?²f = ?·?f = (?/?x,?/?y,?/?z)·(?f/?x,?f/?y,?f/?z) = ?²f/?x²+?²f/?y²+?²f/?z²

i just came
lol at this comment, it looks to me to be the derivative of the gradient or 2nd deriv of the multi variable function with respect to each variable
 

IEC

Elite Member
Super Moderator
Jun 10, 2004
14,469
5,535
136
I took up to multivariable calc and then promptly forgot most of my calc. Guess this thread inspires me to brush up on some of this again :)