math help

[deejayshakur]

it's driving me nuckin futs. my math is really rusty. any help is appreciated.

 

[cirthix]

x+(x^-1.1) = 2
or
(x+x)^-1.1 = 2

?

 

[deejayshakur]

x+(x^-1.1) = 2

sorry

 

[chuckywang]

x=1.

/thread

 

[FleshLight]

x=1 or 1.0950941658536

 

[deejayshakur]

ok...how do you do it on paper? do you need quadratic or just manipulate the exponents?

 

[chuckywang]

Originally posted by: deejayshakur
ok...how do you do it on paper? do you need quadratic or just manipulate the exponents?

You just look at it...you can only find x=1 in your head. You need powerful software to find the other solutions.

 

[Cerb]

Originally posted by: deejayshakur
ok...how do you do it on paper? do you need quadratic or just manipulate the exponents?

No. Simple proptery: 1^anything = 1.

So, 1 + 1^anything = 1 + 1 = 2. The ^-1.1 just throws you off, unless you have to find all solutions (I think around 1.096 is another solution, FI).

 

[deejayshakur]

Originally posted by: Cerb

Originally posted by: deejayshakur
ok...how do you do it on paper? do you need quadratic or just manipulate the exponents?

No. Simple proptery: 1^anything = 1.

So, 1 + 1^anything = 1 + 1 = 2. The ^-1.1 just throws you off, unless you have to find all solutions (I think around 1.096 is another solution, FI).

yea i understand the 1 solution, but the other one was pissing me off. i'm not sure if the prof was expecting people to use software or what. thanks, i figured out what i needed to.

 

[Cerb]

Well, I can't think of how to get the other off the top of my head. If I could, it would have been exact, not an approximation 🙂. I know it's not hard either, I just don't recall how to deal with fractional exponents in there (unless they're the only thing with the variable, but they aren't, here).

 

[biostud]

Originally posted by: deejayshakur
x+(x^-1.1) = 2

sorry

x + 1/x^1.1 = 2

x^2.1 + 1 = 2x

x^2.1 - 2x^1.1 + 1 = 0

x^0.1 * (x^2 -2x) +1 = 0

not entirely sure if that helps or if it's even correct.