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Math Help

P

Prior

Member
1.Write the equation in slope-intercept form of a line that has point (3,-2) with a slope of 3 over 2
2. Write the equation of a line in point-slope form-2 over 3 , -3 over 2 , slope=-2 over 3



For some reason I can't get these problems and like 4 other ones. I will appreciate it if someone can help me go through the steps of these and 4 other problems so I can know how to do it.
 
Slope intercept is as follows:


y = mx + b

m is the slope, b is the y-intercept. For problem 1, and all problems like this, set m equal to the slope. To find b, you plug in known values for x and y and then solve for b. So, to be precise, you have the point (3, -2). You have the slope. So you write:

y = mx + b
-2 = (3/2)*(3) + b

Solve for b.
 
As for the answer, you tell us what you think it is, you should be able to do y = mx very easily by plugging the slope in, do that for both, then I'll help you with b
 
Originally posted by: Prior
is one -4=3*6
Click to expand...

You plugged too many things in.

Lets do it step by step.

For the first problem, plug in the given slope in y=mx+b where m is the slope, leave the rest as it is
 
-2=3 over 2 *3 is what I have so far for one.

For 2 which I have to do in Point Slope I have:

-3-2=-5
3-2=1 so -5

 
Originally posted by: Prior
Anyone know if the answers I got are right?
Click to expand...



(3, -2)
^=x ^=y

slope = m = 3 over 2 = 3/2

you know what x, y, and m are. so plug all that into the equation y=mx + b to get the value for b. then substitute ONLY m and b back into y=mx+b for the general equation of that slope-intercept.

 
People are giving you horrible advice here. The proper, easy way to do it is as follows.

(y-y1) = m(x-x1)

m = 3/2
(x1,y1) = (3,-2)


You should get y+2 = (3/2)(x-3)
or y = (3/2)x - 9/2 - 2
y = (3/2)x - 13/2
 
Originally posted by: silverpig
People are giving you horrible advice here. The proper, easy way to do it is as follows.

(y-y1) = m(x-x1)

m = 3/2
(x1,y1) = (3,-2)


You should get y+2 = (3/2)(x-3)
or y = (3/2)x - 9/2 - 2
y = (3/2)x - 13/2
Click to expand...

^^ ditto. good job silverpig

slope intercept is very basic, like pre-algebra. are you sure its not in your textbook or anything, it should be in most.

even easier way to do it is just write in slope form:

y=mx+b

where m is the slope, and b is the y value of of the y-intercept.

since you are given 3/2 as the slope, substitute that for m, then substitute the given points into the equation. Then solve for b. you will then have b for your equation.
 
For #2 you are given a point (x1,y1) = (-2/3,-3/2) and a slope of m = -2/3

Plug it into y-y1 = m(x-x1) to get

y + (3/2) = (-2/3)(x+2/3)
y + 3/2 = -2x/3 - 4/9
y = -2x/3 - 4/9 - 3/2
y = -2x/3 - 8/18 - 27/18
y = -2x/3 - 35/18
 
Originally posted by: silverpig
People are giving you horrible advice here. The proper, easy way to do it is as follows.

(y-y1) = m(x-x1)

m = 3/2
(x1,y1) = (3,-2)


You should get y+2 = (3/2)(x-3)
or y = (3/2)x - 9/2 - 2
y = (3/2)x - 13/2
Click to expand...


how is it horrible? you still get the same answer in the end. it's not like it was that difficult to begin with that any which way is more efficient 😛
 
Originally posted by: dvdrdiscs
Originally posted by: silverpig
People are giving you horrible advice here. The proper, easy way to do it is as follows.

(y-y1) = m(x-x1)

m = 3/2
(x1,y1) = (3,-2)


You should get y+2 = (3/2)(x-3)
or y = (3/2)x - 9/2 - 2
y = (3/2)x - 13/2
Click to expand...


how is it horrible? you still get the same answer in the end. it's not like it was that difficult to begin with that any which way is more efficient 😛
Click to expand...

Because 10 posts were made with the y = mx + b method and it confused the poor guy. I posted and he got it. Now via PM he's managed to solve a few more on his own.

You could get the same answer if you put everything into a cubic matrix too, but the idea is to make it as simple as possible for the original poster to understand and solve it on his own.
 
Oh man, this brings back memories of middle school! As soon as I read, "Write in slope-intercept form," I immediately remembered y=mx+b. You never forget that $hit! Thanks for the memories.
 
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