Math Help ....

[SaigonK]

I have some problems I am working on and am curios if I am heading in the right direction....if someon wouldnt mind helping out that would be great.


Perform the indicated operation
5x2y(x-y2)(x2+xy2+y4)
Here is what I got:

5x^2y(x-y^2)
5x^2y (+ x - y^2)
Simplify:
5x^3y - 5x^2y^3


And another one:


(a+b)(a2-ab+b2)

(a + b )(+ a^2 - ab + b^2 )
Simplify:
a^3 + a^2b - a^2b - ab^2 + ab^2 + b^3
Combine like terms:
a^3 + b^3


And another:

Factor out the GCF.
56x3y5+40x2y6-16x2y3

56x^3y^5 + 40x^2y^6 - 16x^2y^3
GCF = 8x^2y^3

8x^2y^3 (+ 7xy^2 + 5y^3 - 2)



Now here is one I am having a bith of a time solving, i just dont know what i am supposed to do:

Reduce the rational expression:

x^2-4
----------------
2x^2-x-10


And another one that is the same:

(?x-1)(?x+1)
--------------------------
x^2+x-2


All help is appreciated, all thread crappers can go somewhere else before you even begin your normal BS.
I want help, not answers, I think I have some solved, but others I dont get..

 

[Daishiki]

(x² - 4) / (2x² - x - 10)
break each apart
(x + 2)(x - 2) / (2x - 5)(x + 2)
cancel terms leaves you with
(x - 2) / (2x - 5)

(x - 1)(x + 1) / (x² + x - 2)
factor the denominator polynomial
(x - 1)(x + 1) / (x + 2)(x - 1)
cancel (x-1)
(x + 1) / (x + 2)

use quadratic formula to factor the polynomials if you can't do it in your head

 

[Yossarian]

n/m

 

[Koing]

Originally posted by: xUCIxDaiSHi
(x² - 4) / (2x² - x - 10)
break each apart
(x + 2)(x - 2) / (2x - 5)(x + 2)
cancel terms leaves you with
(x - 2) / (2x - 5)

(x - 1)(x + 1) / (x² + x - 2)
factor the denominator polynomial
(x - 1)(x + 1) / (x + 2)(x - 1)
cancel (x-1)
(x + 1) / (x + 2)

use quadratic formula to factor the polynomials if you can't do it in your head

😀

Good tos ee I can follow that and remember the maths I did.

I know who to turn to for m help later 😀

Koing

 

[SaigonK]

Originally posted by: xUCIxDaiSHi
(x² - 4) / (2x² - x - 10) break each apart (x + 2)(x - 2) / (2x - 5)(x + 2) cancel terms leaves you with (x - 2) / (2x - 5) (x - 1)(x + 1) / (x² + x - 2) factor the denominator polynomial (x - 1)(x + 1) / (x + 2)(x - 1) cancel (x-1) (x + 1) / (x + 2) use quadratic formula to factor the polynomials if you can't do it in your head

Thanks for the info, but do my first two look right?

 

[SaigonK]

here is another one i am having an issue with:

Find the quotient and remainder for the indicated division. Check by using the fact that dividend=(divisor)(quotient)+remainder.
(w3+2w2-3)/(w-2)

and another, but this one seems simple to me:

Simplify the radical expression
?16a^6b^5


EDIT:

ok some of my stuff isnt coming into the forum correctly...click HERE for the problems in word format.

 

[SaigonK]

Originally posted by: xUCIxDaiSHi
(x² - 4) / (2x² - x - 10) break each apart (x + 2)(x - 2) / (2x - 5)(x + 2) cancel terms leaves you with (x - 2) / (2x - 5) (x - 1)(x + 1) / (x² + x - 2) factor the denominator polynomial (x - 1)(x + 1) / (x + 2)(x - 1) cancel (x-1) (x + 1) / (x + 2) use quadratic formula to factor the polynomials if you can't do it in your head

I dont think these are right actually...they are missing the square root symbol.

 

[Daishiki]

Originally posted by: SaigonK

Originally posted by: xUCIxDaiSHi
(x² - 4) / (2x² - x - 10) break each apart (x + 2)(x - 2) / (2x - 5)(x + 2) cancel terms leaves you with (x - 2) / (2x - 5) (x - 1)(x + 1) / (x² + x - 2) factor the denominator polynomial (x - 1)(x + 1) / (x + 2)(x - 1) cancel (x-1) (x + 1) / (x + 2) use quadratic formula to factor the polynomials if you can't do it in your head

I dont think these are right actually...they are missing the square root symbol.

the "?" 's are radicals? enclose whatever's in the radical with parentheses. i don't know if you mean rad(x) + 1 or rad(x+1)

the division one link

rad(16 a^6 b^5), rewritten:
rad(4² (a³)² b (b²)²)
4a³b² rad(b)

 

[SaigonK]

Originally posted by: xUCIxDaiSHi

Originally posted by: SaigonK

Originally posted by: xUCIxDaiSHi (x² - 4) / (2x² - x - 10) break each apart (x + 2)(x - 2) / (2x - 5)(x + 2) cancel terms leaves you with (x - 2) / (2x - 5) (x - 1)(x + 1) / (x² + x - 2) factor the denominator polynomial (x - 1)(x + 1) / (x + 2)(x - 1) cancel (x-1) (x + 1) / (x + 2) use quadratic formula to factor the polynomials if you can't do it in your head

I dont think these are right actually...they are missing the square root symbol.

the "?" 's are radicals? enclose whatever's in the radical with parentheses. i don't know if you mean rad(x) + 1 or rad(x+1) the division one link rad(16 a^6 b^5), rewritten: rad(4² (a³)² b (b²)²) 4a³b² rad(b)

Sorry my bad it was:

(rad then x-1)(rad then x=1)

 

[SaigonK]

Originally posted by: xUCIxDaiSHi

Originally posted by: SaigonK

Originally posted by: xUCIxDaiSHi (x² - 4) / (2x² - x - 10) break each apart (x + 2)(x - 2) / (2x - 5)(x + 2) cancel terms leaves you with (x - 2) / (2x - 5) (x - 1)(x + 1) / (x² + x - 2) factor the denominator polynomial (x - 1)(x + 1) / (x + 2)(x - 1) cancel (x-1) (x + 1) / (x + 2) use quadratic formula to factor the polynomials if you can't do it in your head

I dont think these are right actually...they are missing the square root symbol.

the "?" 's are radicals? enclose whatever's in the radical with parentheses. i don't know if you mean rad(x) + 1 or rad(x+1) the division one link rad(16 a^6 b^5), rewritten: rad(4² (a³)² b (b²)²) 4a³b² rad(b)

link doesnt work... 🙁

 

[SaigonK]

Got this one already! Figured it out. 🙂


Find the quotient and remainder for the indicated division. Check by using the fact that dividend=(divisor)(quotient)+remainder.
(w3+2w2-3)/(w-2)

 

[CrazyPerson]

booooooo