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Looking for a math genius to help me out till June.

J

jsbush

Diamond Member
I'm taking math 436 after school once a week, so I don't have access to a teacher very often. My tutor gives me lots of work to do, but I don't understand it all. If anyone would be kind enough to explain some stuff for me I would really appreciate it.

If this could be done by PM or email it would be great, if not I'll just post it here 😛


Heres what I'm stuck on:

"Discribe the properites of a given quadratic function."
1. Given the following functions:
1) f(x)=x²-3x-4
2) g(x)=2x²-12
3) h(x)=3x²-5x
4) k(x)=-x²+4x-3



a) the corrodinates of the parabola's vertex;
1) (2,6)
2) ???
3) (1,2)
4) (2,1)

Are my answers for 1,3,4 right? Can someone please explain how to get 2)?

Also what do they want me to find out when they ask me

b) the equation of the axis of symmetry;




Could you please not give me the answers but give me an explaination instead? thx.
 


<< If anyone would be kind enough to explain some stuff for me I would really appreciate it. >>

"Explain" or "Give the answers"? 😉
 
Actually I'm not being marked on this at all or anything so the answer is irrelevent but how to get the answer is important. I'm paying 18$ a tutoring sesion and I really want to fully understand this stuff.

Thanks.
 
While I can't help with the problem, I can help you write it in such a way as to be more readable:

1. Given the following functions:
1) f(x)=x²-3x-4
2) g(x)=2x²-12
3) h(x)=3x²-5x
4) k(x)=-x²+4x-3

ALT-0178 to get the ², ALT-0179 will get you a nifty ³.

Viper GTS
 
c'mon it's not that hard - correct me I'm wrong, it's been a while ...

to calculate the vertex of a quadratic eq. = -b/2a for the standard form - f(x)=ax^2+bx+c

the best way to work with algebra is to graph .. you should be able to graph those baby in no time ... get the zeros and vertex and viola you got it ....
-ls
 


<< "Discribe the properites of a given quadratic function."
1. Given the following functions:
1) f(x)=xx-3x-4 2) g(x)=2xx-12
3) h(x)=3xx-5x 4) k(x)=-xx+4x-3

a) the corrodinates of the parabola's vertex;
1) (2,6)
2) ???
3) (1,2)
4) (2,1)
 >>



Okay, I'm using a graphing calc and this is what I got:

1) (2,-6)
2) (0,-12)
3) (1,-2)
4) (2,1)

All I did was graph the equations and use the trace function to find out the vertex. I could be wrong though, only in HS advanced math. Maybe it would help if you could explain what you are studing, like what chapter and all.

As far as the symmetry thing I only assume they are wanting a symmetrical line to the graphs. It will be a vertical line going through the vertex's, like on number two the y-axis would be your line of symmetry.

I could be wrong...
 
Does this help? I just simplified your equations. I did this in my head, but you can get the same results using the quadratic equation. try to graph there and then you will see where the vertex is. (*hint remember that the parabola is symmertic and that when the function equals 0 the graph crosses the x-axis).

1. Given the following functions:
1) f(x)=x²-3x-4 = (x-4)*(x+1)
2) g(x)=2x²-12 = (x-sqrt(6))*(x+sqrt(6))
3) h(x)=3x²-5x = (x-0)*(3x-5)
4) k(x)=-x²+4x-3 = -1*(x-3)*(x-1)

sqrt(x) = the sqaure root fo x
sqrt(6) ~ 2.449
 


<< f(x) = ax^2+bx+c

D = b^2-4ac

vertex:

V(b/2a,-D/4a)

axis of symmetry:

x = b/2a >>

this is correct, but if you are just learning the subject I wouldn't use these (unless you see how to derive them - *hint use the quadratic formula and the quadratic function in the form y=a(x-xo)²+yo where the vertex is (xo,yo) ). just use what you have learned in class.
 
I was taught this as standard form - y = a(x-h)² +h

i.e. 2(x-3)² + 6

The vertex is (3,6), so I would have to say the vertex is (-h,k)
 
Thanks guys, but I'm really confused.

I used the calc and got

1) (2,-6)
2) 0,-12
3) 1,-2
4) 2,1

my teacher said it was ok to use the calc to get simple equations. I've only had 2 hours of tutoring with him so I'll ask him to clearify all this stuff for me.

And the forumla he gave me for quadratic funtions is y=a(x-h)²+k


THank for all the help, really appreciate it.
 
436 is a big step up from 314, I remember. Don't sweat it, just so the assigned problems and you should sail through it. HS teachers are jack@sses IMO because they only accept their own way as the correct way and try to make you memorize 15,000 formulas instead of actually helping you understand. College teachers are much more open-minded. BTW, once you learn calculus you won't have to worry about these retarded formulas 😀

Ice
<-- hated memorizing in high-school
 
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