logic riddle

[chorb]

So 3 men (doesnt matter if they're gay) go to a hotel and book a room, the owner of the hotel tells them its $30 bucks a night (no tax) so each guy pays $10 and they're all set. The 3 men all go up to their room, but meanwhile the owner realizes that he has overcharged them by 5$, the room should have been only $25 for the night, so the owner tells the bellhop to take the money up to the room and give them their $5 back. Along the way the bellhop figures that he will save the guys the trouble of figuring out how to evenly distribute the refund, so the bellhop takes $2 and pockets it, leaving $3 to be divided between the 3 men. The men, not knowing that the bellhop took $2, gladly take the $3 and give $1 to each guy.

Now, each guy has paid $9 for the hotel
$9 x 3guys = $27
and the bellhop pocketed $2
summing to $29, what happened to the last dollar?

 

[imported_electron]

old.

answer: the butler did it.

 

[imported_electron]

Just kidding about the butler. The two dollars that the bellhop took are part of the 27 the men paid. The 27 dollars were paid and three dollars were not, totaling 30 dollars.

 

[Syringer]

I took it and bought a Wendy's junior bacon cheeseburger.

 

[jagec]

they paid $30, actual room rate was $25
The bellhop pockets $2 and gives them $3. So, each man paid $9, and 9x3=27, which is $25 for the room + the $2 "tip"

But the real riddle is...are the men gay?

 

[JEDIYoda]

actually the supposd 3 men are actually 3 women who are cross dressers!!

 

[blahblah99]

I took the $1 and went to the strip club across the street!

 

[chuckywang]

The three men paid a total of $9, for a total of $27. That got divided into $25 for the owner and $2 for the bellhop.

The $2 (bellhop)+$27(three men) calculation is meaningless, since that $2 the bellhop took is part of the overall $27, not in addition to it.