William Gaatjes
Lifer
- May 11, 2008
- 22,175
- 1,402
- 126
So 20 mA x 10 LED's = 200, and the battery is about 570. About 2, almost 3 hours. Not really good.
Try putting them in series as well. That increases efficiency.
It all depends on the forward voltage of the led.
If 1 led works on 3,5V, you can put 2 in series for 7V. You have 9 Volts to begin with.
9V-7V = 2V left. Now the forward current limiting resistor is just 2/0.02 = 100 Ohm.
That will double the amount of lightning time you have compared to one led.
Try choosing a battery as a source with the highest voltage close to N x led forward voltage.
With 1 led it is 9V - 3,5V = 5,5V. 5,5 / 0.02 = 275 Ohm.
It is all about power draw and efficiency. You want all the power in the led and not in the resistor.
P=U*I .
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